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Lesechka [4]
3 years ago
5

¿Por qué se generan rayos (tormenta eléctrica) cuando un volcán hace erupción ?

Chemistry
1 answer:
rosijanka [135]3 years ago
5 0

Answer:

Los relámpagos volcánicos surgen de la colisión y fragmentación de partículas de ceniza volcánica (y, a veces, hielo), que generan electricidad estática dentro de la columna volcánica, lo que lleva al nombre de tormenta eléctrica sucia. La convección húmeda y la formación de hielo también impulsan la dinámica de la pluma de erupción y pueden desencadenar rayos volcánicos. por cierto utilicé un traductor espero que esto ayude ^^

Explanation:

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Write the scientific term.
Reil [10]

Answer:  Solubility.

Explanation:

Solubility is defined as the maximum amount of solute dissolved per 100 g of the solvent at a certain fixed temperature to form a saturated solution.

STP condition is Standard Temperature and Pressure condition which is  temperature of 273 K and pressure of 1 atm.

Thus the scientific term for "the number of grams of solute dissolved in 100 g of the solvent to form a saturated solution at STP​" is called as Solubility.

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3 years ago
Which would most likely cause a person to produce antibodies?
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Answer:

receiving a vaccination

Explanation:

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Define unit<br>hi hope u have a great day​
Crank

Answer:

<em><u>Unit</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>quantity</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>constant</u></em><em><u> </u></em><em><u>magnitude</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>used</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>measure</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>magnitudes</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>quantities</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>same</u></em><em><u> </u></em><em><u>nature</u></em><em><u>.</u></em><em><u> </u></em>

Explanation:

<h2>HOPE IT WILL HELP YOU✌✌✌✌✌</h2>
6 0
3 years ago
How do we measure the mass of an extrasolar planet?
Degger [83]
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4 0
3 years ago
The enthalpy of solution (∆H) of KOH is -57.6 kJ/mol. If 3.66 g KOH is dissolved in enough water to make a 150.0 mL solution, wh
Wewaii [24]

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

Qr+Qa = 0\\\\Qa = -Qr = 3.76 kJ

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

150.0 mL \times \frac{1.02g}{mL}  = 153 g

Given the specific heat capacity of the solution (c) is 4.184 J/g・°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

Qa = c \times m \times \Delta T\\\\\Delta T = \frac{Qa}{c \times m} = \frac{3.76 \times 10^{3}J  }{\frac{4.184J}{g.\° C }  \times 153g} = 5.87 \° C

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

Learn more: brainly.com/question/4400908

7 0
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