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Ilia_Sergeevich [38]
3 years ago
9

The change in electric potential energy per unit charge is

Physics
2 answers:
klemol [59]3 years ago
6 0

D-Volatge / gravity and current aren’t units and amperes is the loop of electrical current

Black_prince [1.1K]3 years ago
4 0

D)

Voltage is the change in electric potential energy per unit charge. It is sometimes called the electric potential difference.

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An object of mass 3.07 kg, moving with an initial velocity of 5.07 m/s, collides with and sticks to an object of mass 2.52 kg wi
Alenkasestr [34]

Answer:

This is an inelastic collision. This means, unfortunately, that KE cannot save you, at least in the problem's current form.  

Let's see what conservation of momentum in both directions does ya:

Conservation in the x direction:

Only 1 object here has a momentum in the x direction initally.  

m1v1i + 0 = (m1 + m2)(vx)

3.09(5.10) = (3.09 + 2.52)Vx

Vx = 2.81 m/s

Explanation:

Conservation in the y direction:

Again, only 1 object here has initial velocity in the y:

0 + m2v2i = (m1 +m2)Vy

(2.52)(-3.36) = (2.52 + 3.09)Vy

Vy = -1.51 m/s

++++++++++++++++++++

Now that you have Vx and Vy of the composite object, you can find the final velocity by doing Vf = √Vx^2 + Vy^2)

Vf = √(2.81)^2 + (-1.51)^2

Vf = 3.19 m/s

3 0
4 years ago
1. How long would the car in Sample Problem C take to come to a stop from its initial velocity of 20.0 m/s to the west? How far
Brilliant_brown [7]

The time taken, and the distance travelled by the car before stop, will be 5.3 second and -53.3 m west.

<h3>What is the distance?</h3>

The length of the path traveled by the body is known as the distance covered by the body.

Distance is a 1-dimensional phenomenon. its unit is a meter(m). The distance can be found by the product of velocity and time.

The given data in the problem will be

u is the initial velocity =20m/sec

t is the time =?

d is the distance =?

From the Newtons second law;

\rm  F \triangle t = \triangle P \\\\ \triangle t = \frac{\triangle P }{F} \\\\ \triangle t = \frac{m(v_f-v_i)}{F} \\\\ \ \triangle t = \frac{2240 (0-20))}{8410} \\\\ \triangle t = 5.3 \ sec \\\

The distance travelled before the car stop is,

\rm \triangle t = \frac{1}{2} (v_f+v_i)\traingle t \\\\ \traingle x = \frac{1}{2} (-20+0)5.3 \\\\\ \triangle x= -53.3 m \ west

Hence,the time taken, and the distance travelled by the car before stop, will be 5.3 second and -53.3 m west.

To learn more about the distance, refer to the link;

brainly.com/question/989117

#SPJ1

6 0
2 years ago
How much of the Moon is always illuminated one time? Explain your answer.
Natalija [7]

Answer:

50% of it .

Explanation:

50% of it is illuminated by the Sun.

6 0
3 years ago
A 5 kg block moves with a constant speed of 10 ms to the right on a smooth surface where frictional forces are considered to be
nirvana33 [79]

Answer:

Work done, W = 19.6 J

Explanation:

It is given that,

Mass of the block, m = 5 kg

Speed of the block, v = 10 m/s

The coefficient of kinetic friction between the block and the rough section is 0.2

Distance covered by the block, d = 2 m

As the block passes through the rough part, some of the energy gets lost and this energy is equal to the work done by the kinetic energy.

W=\mu_kmgd

W=0.2\times 5\times 9.8\times 2

W = 19.6 J

So, the change in the kinetic energy of the block as it passes through the rough section is 19.6 J. Hence, this is the required solution.

5 0
3 years ago
Read 2 more answers
Please explain how to solve 17 and 18
andriy [413]

Answer:

17. h = l − l cos θ

18. 1.40 m

Explanation:

Let's call d the height of the triangle.  We can then say:

h = l − d

Using trig, we can write d in terms of l and θ:

d = l cos θ

h = l − l cos θ

If l = 6 m and l cos θ = 40°:

h = 6 − 6 cos 40

h ≈ 1.40

3 0
3 years ago
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