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rodikova [14]
2 years ago
14

Calculate the work done in moving a charge of 2 coulombs across 2 points having a potential difference of 12 volts

Physics
1 answer:
Veseljchak [2.6K]2 years ago
8 0

Answer:

Work is done in moving a charge of 2 coulomb across two points having a potential difference of 12 volt is 24 joule .

Explanation:

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A mass on the end of a spring undergoes simple harmonic motion. At the instant when the mass is at its maximum displacement from
Mrac [35]

Answer:

C) True. At maximum displacement, its instantaneous velocity is zero.

Explanation:

The simple harmonic movement is given by

        x = A cos wt

Speed

        v = - A w sin wt

At the point of maximum displacement x = A

       A = A cos wt

      cos wt = 1

      wt = 0

We replace the speed

       v = -Aw sin 0 = A w

Speed ​​is maximum

Let's review the claims

A) False. Speed ​​is zero

B) False. It can be determined

C) True. Agree with our result

D) False. When one is maximum the other is minimum

4 0
2 years ago
A raging bull of mass 700 kg runs at 36 km/h .How much kinetic energy does it have ?
Ipatiy [6.2K]

Answer:

Use equation for kinetic energy: Ek=mV²/2

m=700 kg

V=10m/s

Ek=700kg*100m²7s²/2

Ek=35000 J=35kJ

Explanation:

Hope this helps you

Do mark me as brainliest

5 0
3 years ago
Read 2 more answers
How can two machines appear identical and yet not have the same actual mechanical advantage
STatiana [176]
There are many factors which contributes as to how a machine will be processing the input energy and convert it to output energy. Even with identical mechanism, these factors will have major effect on the output. Some factors are deflection, friction and wear. Some system maybe exposed to poor lubrication than the other which'll produce more friction and wear thus lower mechanical advantage.
4 0
3 years ago
Which of the following are examples of projectile motion?
denis-greek [22]

Answer:

A or C    I would pick C

Explanation:

8 0
3 years ago
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A motorcyclist accelerates from rest to 10 mi/hr. what is the change in velocity
gulaghasi [49]

The change in velocity is 10 mi/h (4.47 m/s)

Explanation:

The change in velocity of the motorcyclist is given by

\Delta v = v-u

where

v is the final velocity

u is the initial velocity

In this problem, we have

u = 0 (the motorbike starts from rest)

v = 10 mi/h

Therefore, the change in velocity is

\Delta v = 10 -0 = 10 mi/h

And keeping in mind that

1 mile = 1609 m

1 h = 3600 s

We can convert it into m/s:

\Delta v = 10 \frac{mi}{h} \cdot \frac{1609 m/mi}{3600 s/h}=4.47 m/s

Learn more about velocity:

brainly.com/question/5248528

#LearnwithBrainly

6 0
2 years ago
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