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3 years ago

Calculate the work done in moving a charge of 2 coulombs across 2 points having a potential difference of 12 volts

Physics

1 answer:

Veseljchak [2.6K]3 years ago

8 0

Answer:

Work is done in moving a charge of 2 coulomb across two points having a potential difference of 12 volt is 24 joule .

Explanation:

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Does spilled milk have higher or lower entropy

Lady_Fox [76]

Due to the theory of dried enzimes and philosophy, the spilled milk would have an higher entropy.

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3 years ago

The power in a circuit is 2 W and the voltage is 20 VDC. What's the circuit current?

Aliun [14]

Answer:

Power in the circuit is 0.1 amp

Explanation:

The power in the circuit is given by the formula

P = V x I

Where P is Power, V is voltage supplied and I is current in circuit.

so, I = P/v

= 2/20

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1 year ago

Joe is measuring the time it takes for a ball to roll down a ramp. In this experiment Joe takes the measurement 5 times and gets

PolarNik [594]

Step by step solution :

standard deviation is given by :

$\sigma = \sqrt\dfrac{{\sum (x-\bar{x})^2}}{n}$

where, $\sigma$ is standard deviation

$\bar{x}$ is mean of given data

n is number of observations

From the above data, $\bar{x}=24.88$

Now, if $x=24.8$ , then $(x-\bar{x})^2=0.0064$

If $x=23.9$ , then $(x-\bar{x})^2=0.9604$

if $x=26.1$ , then $(x-\bar{x})^2=1.4884$

If $x=25.1$ , then $(x-\bar{x})^2=0.0484$

If $x=24.5$ , then $(x-\bar{x})^2=0.1444$

so, $\sum (x-\bar{x})^2 =\frac{0.0064+0.9604+1.4884+0.0484+0.1444}{5}$

$\sum (x-\bar{x})^2 =2.648$

$\sqrt{\sum \frac{(x-\bar{x})^2}{n}}$

$\sigma =0.7277$

No, Joe's value does not agree with the accepted value of 25.9 seconds. This shows a lots of errors.

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2 years ago

All ions are atoms with a (2 points)

Andrews [41]

This could be wrong but I am giving a decent suggestion: All ions are atoms with a negative charge.

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3 years ago

Read 2 more answers

The wheels of a car have radius 12 in. and are rotating at 600 rpm. Find the speed of the car in mi/h.

guajiro [1.7K]

Answer:

21.4 mph

Explanation:

Circumference of tire in FEET = pi * d = pi * 1 ft = pi feet

pi feet x 600 rot/min * 60 min /hr * 1 mile / 5280 feet = 21.4 mph

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10 months ago