Answer:
a = 2.22 [m/s^2]
Explanation:
First we have to convert from kilometers per hour to meters per second
We have to use the following kinematics equation:
where:
Vf = final velocity = 11.11 [m/s]
Vi = initial velocity = 0
a = acceleration [m/s^2]
t = time = 5 [s]
The initial speed is taken as zero, as the car starts from zero.
11.11 = 0 + (a*5)
a = 2.22 [m/s^2]
Answer:
The magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.
Explanation:
Given;
distance between the parallel wires, r = 5.0 cm = 0.05 m
current in the first wire, I₁ = 1.65 A
current in the second wire, I₂ = 3.25 A
The magnitude of the force per unit length between the two wires is calculated as follows;
Therefore, the magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.
Answer:
(a) Magnetic field at the center of the loop is 4.08 x 10⁻⁵ T
(b) Magnetic field at the axis of the loop is 5.09 x 10⁻⁹ T
Explanation:
Given :
Diameter of the circular loop = 2 cm
Radius of the circular loop, R = 1 cm = 0.01 m
Current flowing through the circular wire, I = 650 mA = 650 x 10⁻³ A
(a) Magnetic field at the center of circular loop is determine by the relation:
Here μ₀ is vacuum permeability constant and its value is 4π x 10⁻⁷ T m²/A.
Substitute the suitable values in the above equation.
B = 4.08 x 10⁻⁵ T
(b) Distance from the center of the loop, z = 20 cm = 0.2 m
Magnetic field at the point on the axis of the loop is determine by the relation:
B = 5.09 x 10⁻⁹ T