How many moles of water are in 1.23 x 10^18 water molecules?
2 answers:
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Explanation:
The given reaction equation is as follows.
Hence, initial moles of HCN will be as follows.
Moles = Molarity × Volume
=
= 48.072 mol
Now, we will calculate the volume of NaOH as follows.
= 70.57 ml
At the equivalence point, moles of both HCN and NaOH will be equal. And, total volume will be as follows.
120 ml + 70.57 ml = 190.57 ml
Initial concentration of is as follows.
= 0.25 M
Now, the equilibrium equation will be as follows.
Initial: 0.25
Equilbm: 0.25 - x x x
Expression to find is as follows.
We know that,
= antilog (-9.21)
=
As,
x =
Now, we will calculate the pH as follows.
pOH =
as pOH = 2.698
And, pH + pOH = 14
pH = 14 - 2.698
= 11.30
Thus, we can conclude that pH at equivalence is 11.30.