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ss7ja [257]
3 years ago
15

203 red, 117 white, and 28 blue. She asked the students to draw marbles from the box, one at a time and without looking. What is

the minimum number of marbles which students should take from the box to ensure that at least three of them are of the same colour?
Mathematics
1 answer:
grandymaker [24]3 years ago
8 0

Answer:

7

Step-by-step explanation:

Since the goal is to draw three marbles of the same colour, regardless of which colour that is, the worst possible scenario would be drawing two marbles of each color in the first six picks (2 red, 2 white and 2 blue). At this point, with the 7th pick, no matter what colour marble the student picks will form three of the same kind.

Therefore, the minimum number of marbles which students should take from the box to ensure that at least three of them are of the same colour is 7.

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Solve: x^+4/x-1 = 5/x-1
AlexFokin [52]
The first step for solving this equation is to determine the defined range.
\frac{ x^{4}  }{x-1} = \frac{5}{x-1}, x ≠ 1
Remember that when the denominators of both fractions are the same,, you need to set the numerators equal. This will look like the following:
x^{4} = 5
Take the root of both sides of the equation and remember to use both positive and negative roots.
x +/- \sqrt[4]{5}
Separate the solutions.
x = \sqrt[4]{5}           , x ≠ 1
x = -\sqrt[4]{5} 
Check if the solution is in the defined range.
x = \sqrt[4]{5} 
x = -\sqrt[4]{5} 
This means that the final solution to your question are the following:
x = \sqrt[4]{5}          
x = -\sqrt[4]{5} 
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Aneli [31]

Answer:

a. 1/2

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c. 2.5

Step-by-step explanation:

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Which equation is the direct variation equation if f(x) varies directly with x and f(x)=-18 when x=3
Otrada [13]
\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  \stackrel{f(x)}{y}=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\
\textit{we also know that }
\begin{cases}
y=-18\\
x=3
\end{cases}\implies -18=k3
\\\\\\
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