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azamat
3 years ago
14

An 8-passenger Learjet has a force of gravity of 6.6x10^4 [down] acting on it as it travels at a constant velocity of 6.4x10^2 k

m/h [W]. If the forward thrust provided by the engines is 1.3x10^4 N [W], determine: a.) the upward lift on the plane b.) the force due to air resistance on the plane
Physics
1 answer:
IgorC [24]3 years ago
7 0
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PLS HELP FOR PHYSICS PLS
Mumz [18]

Answer:

Chinese app which is number

Explanation:

7 0
3 years ago
The speed of light in vinegar is 2.30 x 10^8 m/s. Determine the index of refraction. (2​
pantera1 [17]

Answer:

n _{v} =  \frac{c}{v}  \\  =  \frac{3 \times  {10}^{8} }{2.30 \times  {10}^{8} }  \\  = 1.30

6 0
3 years ago
Mars has a mass of about 6.24 Ã 1023 kg, and its moon phobos has a mass of about 9.2 Ã 1015 kg. if the magnitude of the gravitat
Effectus [21]
Given: Mass of Mars Mm = 6.24 x 10²³ Kg;  

           Mass of Phobos Mp = 9.2 x 10¹⁵ Kg

           Gravitational  Force F = 4.47 X 10¹⁵ N

           Gravitational constant G = 6.67 X 10⁻¹¹ N m²/Kg²

           Radius r = ?

Formula: F = GMmMp/r²  derive r

               r = √GMmMp/F

     r = √(6.67 x 10⁻¹¹ N m²/Kg²)(6.24 x 10²³ Kg)(9.2 x 10¹⁵ Kg)/4.47 x 10¹⁵ N

     r = √(6.67 x 10⁻¹¹ N m²/Kg²)5.74 x 10³⁹ Kg²/4.47 x 10¹⁵ N

     r = √8.57 x 10¹³ m

     r = 9,257,429 m

or r = 9.26 x 10⁶ m

8 0
4 years ago
A 75.0-kg person is riding in a car moving at 20.0 m/s when the car runs into a bridge abutment. (a) calculate the average force
iragen [17]

(a) -1.5\cdot 10^6 N

First of all, we need to calculate the acceleration of the person, by using the following SUVAT equation:

v^2 -u ^2 = 2ad

where

v = 0 is the final velocity

u = 20.0 m/s is the initial velocity

a is the acceleration

d = 1.00 cm = 0.01 m is the displacement of the person

Solving for a,

a=\frac{v^2-u^2}{2d}=\frac{0-20.0^2}{2(0.01)}=-20000 m/s^2

And the average force on the person is given by

F=ma

with m = 75.0 kg being the mass of the person. Substituting,

F=(75)(-20000)=-1.5\cdot 10^6 N

where the negative sign means the force is opposite to the direction of motion of the person.

b) -1.0\cdot 10^5 N

In this case,

v = 0 is the final velocity

u = 20.0 m/s is the initial velocity

a is the acceleration

d  = 15.00 cm = 0.15 m is the displacement of the person with the air bag

So the acceleration is

a=\frac{v^2-u^2}{2d}=\frac{0-20.0^2}{2(0.15)}=-1333 m/s^2

So the average force on the person is

F=ma=(75)(-1333)=-1.0\cdot 10^5 N

7 0
4 years ago
- A particular light source gives off light waves with a measured wavelength of
skad [1K]

Answer:

f = 1.5 x 10¹⁵ Hz

Explanation:

Light is an electromagnetic wave and we know that the speed of light is a constant which is 

3 x 10⁸ m/s.

Knowing this; v = λ x f

λ = wavelength

f= frequency of light

v = seed of light

f = v/λ

f =  3 x 10⁸m/s / 2.0 x 10-⁷ m

f = 1.5 x 10¹⁵ Hz

8 0
2 years ago
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