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azamat
3 years ago
14

An 8-passenger Learjet has a force of gravity of 6.6x10^4 [down] acting on it as it travels at a constant velocity of 6.4x10^2 k

m/h [W]. If the forward thrust provided by the engines is 1.3x10^4 N [W], determine: a.) the upward lift on the plane b.) the force due to air resistance on the plane
Physics
1 answer:
IgorC [24]3 years ago
7 0
Jdnkdudjdjdjfimkgkfkmkdkfkckv
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See the person on the right side of the front car. Six reference points could be used to show that the person is in / is NOT in
Rasek [7]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

1. According to person standing on ground ~

  • The person is in motion

2. According to The car ~

  • The person is not in motion

3. According to the Seat ~

  • The person is not in motion

4. According to another person on ride ~

  • The person is not in motion

5. According to the track ~

  • The person is in motion

6. According to the Sun ~

  • The person is in motion

I hope that's what you were looking for, goodluck for your assignment ~

7 0
2 years ago
A laptop can convert 400J of electrical energy into a 240J of light and sound. What is the efficiency? Where does the rest of th
Blababa [14]
Efficiency = (Wanted) energy out ÷ energy in × 100

Energy in = 400J
Wanted Energy out = 240J

Energy cannot be used up, only transferred, so the remaining energy is most likely to be transferred into unwanted energy (loss of energy) such as heat energy.

Efficiency = 240 ÷ 400 × 100
Efficiency = 0.6 × 100
Efficiency = 60%
8 0
3 years ago
When beryllium-7 ions (m = 11.65 × 10-27 kg) pass through a mass spectrometer, a uniform magnetic field of 0.205 T curves their
AysviL [449]

Answer:

ratio =0.3075 T

Explanation:

The magnetic field B creates a force on a moving charge such that

F = qvB

Now this causes a centripetal acceleration

F =  = mv^2/r

 so

qvB = mv^2/r ...........(i)

B = mv/(rq)  ...............(ii)

If  accelerating potential V is  same and  then  kinetic energy equals the potential energy difference

\frac{1}{2} mv^2 = Vq

v = \sqrt{(2Vq/m)}      put these value in equation (ii)

B = m\frac{\sqrt{(2Vq/m)} }{rq}  

simplifying we get  

B =m \frac{(\sqrt{ 2Vm/q})}{r}

for same location r will be same in both case

B_{7} = \frac{ \sqrt{(m_{7})(2V/q) }}{r}      ..............(iii)

B_{10} = \frac{ \sqrt{(m_{10})(2V/q) }}{r}    ..........(iv)

 dividing (iv) and (iii) equation we get

\frac{B_{10}}{B_{7}}   =   \sqrt{\frac{m_{10}}{{m_7}} }

{B_{10}}  =  B_{7}  \sqrt{\frac{m_{10}}{{m_7}} }

B_{10}       = 0.2574T\sqrt{\frac{  (1.663x10^-26}{(1.165x10^-26)}

so on solving we get  

             =0.3075 T

5 0
3 years ago
Anther graph question pls help thank you
Lera25 [3.4K]
I believe the answer to be she stopped for 4 mins
8 0
3 years ago
Read 2 more answers
In the symbol 4/2He the subscript 4 is the _____for helium and 2 is the subscript for helium
Svet_ta [14]
^{4}_{2}}He
The 4 signifies the atomic weight, and the 2 subscribes the element's atomic number(aka the number of protons in the atom).
7 0
3 years ago
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