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azamat
3 years ago
14

An 8-passenger Learjet has a force of gravity of 6.6x10^4 [down] acting on it as it travels at a constant velocity of 6.4x10^2 k

m/h [W]. If the forward thrust provided by the engines is 1.3x10^4 N [W], determine: a.) the upward lift on the plane b.) the force due to air resistance on the plane
Physics
1 answer:
IgorC [24]3 years ago
7 0
Jdnkdudjdjdjfimkgkfkmkdkfkckv
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Hemoglobin is a molecule found in blood used to transport oxygen throughout the body. What type of biological compound is this?
Hatshy [7]

Answer:

Hemoglobin is a protein (because it's a molecule that's not a living part of the cell but aids in cell processes).

8 0
4 years ago
In this relationship, the barnacles derive benefit. There is not benefit or harm to the whale. This relationship is an example o
klio [65]
Commensalism: only one species benefits while the other is neither helped nor
harmed
so the relationship is Commensalism
4 0
4 years ago
Read 2 more answers
I will mark as the brainliest answer<br><br>plz 8,9,10​
blagie [28]

Answer:

8.  acceleration = \dfrac{d(velocity)}{d(time)}  = 1 unit .

9. acceleration = \dfrac{d(velocity)}{d(time)}  = -1 unit.

10. acceleration = \dfrac{d(velocity)}{d(time)}  = 0 units.

Explanation:

8. i) acceleration = velocity / time

  ii) In this figure velocity = time

  iii) therefore acceleration = \dfrac{d(velocity)}{d(time)} = 1 unit .

9. i) acceleration = velocity / time

  ii) In this figure 4 = m + 5, therefore m = -1

     therefore velocity = (-0.5 \times time) + 5

  iii) therefore acceleration = \dfrac{d(velocity)}{d(time)}  = -1 units.

10.) velocity is constant at 2

     therefore acceleration = \dfrac{d(velocity)}{d(time)}  = 0 units

5 0
4 years ago
An arrow is moving at 35 m/s and travels for 5 seconds. How far did the arrow travel?
noname [10]

Answer:

175m

Explanation:

So it’s travelling at 35metres/1second so if we want to find 5 seconds we can do this…

\frac{35}{1}  \frac{x}{5}....   so 35x5 ÷ 1 = 175m/5 seconds

6 0
3 years ago
Read 2 more answers
1. Some ripples spread across a pond with a frequency of 5 Hz. How much would be the period of these ripples.
Scilla [17]

1)The period of these ripples will be 0.2 sec.

2)The time period of sound wave will be 100 Hz.

3)The frequency of the sound wave will be 5×10⁶ Hz.

<h3>What is frequency?</h3>

Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.

Frequency is given by the formula as,

Frequency of  ripples (f₁)=5 Hz

The period of these ripples will be;

T₁=1/f₁

T₁=1/5

T₁=0.2 sec

The time period of sound wave (T)=0.01 seconds

The time period of sound wave;

f=1/T

f=1/0.01

f=100 Hz

Time period of A radio wave = 0.0000002 seconds

The frequency of the sound wave is;

f=1/T

f=1/0.0000002

f=5×10⁶ Hz

Hence,the period of these ripples will be 0.2 sec.

To learn more about the frequency, refer to the link;

brainly.com/question/14926605

#SPJ1

6 0
3 years ago
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