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2 years ago

Can someone help answer question 8?

Physics

2 answers:

tigry1 [53]2 years ago

5 0

Star A - (color) red-orange (type) main sequence

Star B - (color) yellow (type) supergiant

Star C - (color) blue-white (type) white dwarf

Star D - (color) yellow (type) main sequence

*im pretty sure these are correct if I remember clearly*

Liono4ka [1.6K]2 years ago

4 0

Answer:

A- Orange-main sequences

B- Red-red supergiant

C- White-White dwarf

D- Yellow-Red giant

Explanation: there's picture on the internet

'star types chart' 'star types and sizes'

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A radio has a 1.3 A current. If it has a resistance of 35 Ω, what is the potential difference?

DedPeter [7]

Answer:

Explanation:

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2 years ago

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As part of a safety investigation, two 1900 kg cars traveling at 20 m/s are crashed into different barriers. Part A Find the ave

DedPeter [7]

Answer:

- $29.2\times 10^{3} N$

Explanation:

We are given that

Mass of cars= m=1900 kg

Initial speed of car=u=20 m/s

Final speed of car=v=0

Time= $\Delta t$ =1.3 s

We have to find the average force exerted on the car.

Average force= $\frac{change\;in\;momentum}{\Delta t}$

$F_{avg}=\frac{mv-mu}{1.3}$

$F_{avg}=\frac{1900(0)-1900(20)}{1.3}$

$F_{avg}=\frac{-38000}{1.3}=-29.2\times 10^{3} N$

Hence, the average force exerted on the car that hits a line of water barrels=- $29.2\times 10^{3} N$

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3 years ago

Juan's mother drives 12.5 miles southwest to her favorite shopping mall. What is the velocity of her

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Answer:

Calculate using the formula

Explanation:

velocity= displacement (m)/time(s)

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2 years ago

g Three masses are located in the x- y plane as follows: a mass of 6 kg is located at (0 m, 0 m), a mass of 4 kg is located at (

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Answer:

Xcm = (6 * 0 + 4 & 3 + 2 * 0) / 12 = 1

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2 years ago

A large aquarium of height 5.00 m is filled with fresh water to a depth of 2.00 m. One wall of the aquarium consists of thick pl

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Answer:

total force = 4.704 × $10^5$ N

Explanation:

given data

height = 5 m

depth = 2 m

thick plastic = 8.00 m

depth = 4.00 m

solution

first we get here force in which aquarium fill with depth 2 m

dF = PdA ......1

F = ∫PdA

F = ∫ϼgy(wdy)

F = ϼgw ∫ y dy

F = ϼgw × $\frac{y^2}{2}$ .................2

F = $1000 \times 9.8 \times 8 \times \frac{2^2}{2}$

F = 1.568 × $10^5$ N

and

now we get here force for depth 4 m

put here value in equation 2

F = $1000 \times 9.8 \times 8 \times \frac{4^2}{2}$

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so that here

total force will be

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2 years ago