You will use candela for comparing.
Answer:
(a) E = [2ξ] / [1+2]]
(b) S = k.ln(1+2) + [ξ] / T[1+2]]
(c) S = k.ln 3 (These values directly obtained from the result of (b) when T⇒0 & T⇒∞.)
Explanation:
Given:
One of three quantum states labeled by the quantum numbers m,
Where m = -1 , 0 or 1
A nucleus has the same energy E= e in the state m = 1 & m = -1
Compared with an energy E = 0 in the state m = 0.
Answer:
the names.
Explanation:
they have different from my point of view but thats it
Answer:
2.7 J
Explanation:
From the question,
The Net work done by the crate = Work done by the crate in moving if through a distance- work done against friction.
W = Fd-F'd.................... Equation 1
Where F = force applied to the crate, d = distance moved by the crate, F' = force of friction
Given: F = 2.4 N, F' = 0.6 N, d = 1.5 m
Substitute these values into equation 1
W = 2.4(1.5)-0.6(1.5)
W = 3.6-0.9
W = 2.7 J