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sleet_krkn [62]
3 years ago
12

Calculate the volume of 6 M acetic acid needed to prepare 100 mL of a 0.10 M acetic acid (CH3COOH) solution.

Chemistry
1 answer:
Zina [86]3 years ago
8 0

Answer:

V = 1.66mL acetic acid

Explanation:

dilution formula:

V1*C1 =V2*C2

⇒ V1*(6M) = (100mL)*(0.1M)

⇒ V1 =( (100mL) * (0.1M) ) / (6M)

⇒ V1 = 1.66mL acetic acid

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A) The average molecular speed in a sample of Ar gas at a certain temperature is 391 m/s. The average molecular speed in a sampl
diamong [38]

<u>Answer:</u>

<u>For A:</u> The average molecular speed of Ne gas is 553 m/s at the same temperature.

<u>For B:</u> The rate of effusion of SO_2 gas is 1.006\times 10^{-3}mol/hr

<u>Explanation:</u>

<u>For A:</u>

The average molecular speed of the gas is calculated by using the formula:

V_{gas}=\sqrt{\frac{8RT}{\pi M}}

     OR

V_{gas}\propto \sqrt{\frac{1}{M}}

where, M is the molar mass of gas

Forming an equation for the two gases:

\frac{V_{Ar}}{V_{Ne}}=\sqrt{\frac{M_{Ne}}{M_{Ar}}}          .....(1)

Given values:

V_{Ar}=391m/s\\M_{Ar}=40g/mol\\M_{Ne}=20g/mol

Plugging values in equation 1:

\frac{391m/s}{V_{Ne}}=\sqrt{\frac{20}{40}}\\\\V_{Ne}=391\times \sqrt{2}=553m/s

Hence, the average molecular speed of Ne gas is 553 m/s at the same temperature.

<u>For B:</u>

Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation for this follows:

Rate\propto \frac{1}{\sqrt{M}}

Where, M is the molar mass of the gas

Forming an equation for the two gases:

\frac{Rate_{SO_2}}{Rate_{Xe}}=\sqrt{\frac{M_{Xe}}{M_{SO_2}}}          .....(2)

Given values:

Rate_{Xe}=7.03\times 10^{-4}mol/hr\\M_{Xe}=131g/mol\\M_{SO_2}=64g/mol

Plugging values in equation 2:

\frac{Rate_{SO_2}}{7.03\times 10^{-4}}=\sqrt{\frac{131}{64}}\\\\Rate_{SO_2}=7.03\times 10^{-4}\times \sqrt{\frac{131}{64}}\\\\Rate_{SO_2}=1.006\times 10^{-3}mol/hr

Hence, the rate of effusion of SO_2 gas is 1.006\times 10^{-3}mol/hr

8 0
3 years ago
A creative super(hero/villian) using the element Zinc in the name
SCORPION-xisa [38]
Captain Zinc, Zincatron, Zincafier, Zinckers, Zincman, Zincit, etc. Please mark me brainliest I'm trying to level up

6 0
3 years ago
A microscope containing two or more lenses is an
kicyunya [14]
<span> A compound <span>lens microscope. </span></span>
6 0
3 years ago
What kind of bond will form between the atoms?
just olya [345]

Answer:- (i) phosphorous and chlorine is polar covalent.

(ii) potassium and oxygen is ionic.

(iii) fluorine and fluorine is nonpolar covalent.

(iv) copper and aluminum is metallic.

(v) carbon and fluorine is polar covalent.

(vi) carbon and hydrogen is nonpolar covalent.

(vii) Aluminum and oxygen is ionic.

(viii) silver and copper is metallic.

Explanations:- An ionic bond forms between a metal and a non metal by the transfer of metal atom valence electrons to the non metal. In (ii) and (vii) the bond is between a metal and a non metal. Potassium is a metal and oxygen is non metal, so the bond between them is ionic. Similarly, Aluminum is a metal and oxygen is a non metal, so the bond between them is also ionic.

Metallic bond is formed between metals only. In (iv) we have metals copper and aluminum and in (viii) we have metals silver and copper. So, there would be metallic bond only.

Covalent bond is formed by the sharing of electrons between non metals. If the bond is between two similar non metals for example H and H, Cl and Cl, N and N etc then it is known as nonpolar covalent as the shared electrons are between both the non metals.

If the bond is formed between two different non metals like C and F, H and Cl etc then it is known as polar covalent as the shared electrons are more towards the more electron negative atom and due to which the highly electron negative atom has partial negative and the less electron negative atom has partial positive charge.

Note:- Even if the bond is between two different non metals but the electron negativity difference is too low then it is considered as nonpolar covalent.

Electron negativity difference between C and H is very low and so the C-H bond is considered as nonpolar covalent.


6 0
3 years ago
ITUS PIOLO
Oksi-84 [34.3K]

Answer:

\boxed{ \tt{187.5g}}

Explanation:

let \: the  \:  o_m \: be  \to \:  1500g\\ let \: the  \: h_l: be \to  20s\\ for \: every \: 20s : o_m \: is \: reduced\: by \:  \frac{1}{2}  \to \\ hence \: after \: 1min \: (60s = three \: 20s) \\ hence \to \\ after \: the \: first \: 20s \: o_m =  \frac{1500}{2}  = 750g\\ after \: the \: second \: 20s \: o_m =  \frac{750}{2}  = 375g \\ after \: the \: third \: 20s \: o_m =  \frac{375}{2}  = 187.5g \\ hence \: after \: a \: minute \: the \: orgial \: sample :  \\  \boxed{ \tt{o_m : 1500g \: will \: be  \: to \: 187.5g}}

3 0
3 years ago
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