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3 years ago

Calculate the volume of 6 M acetic acid needed to prepare 100 mL of a 0.10 M acetic acid (CH3COOH) solution.

Chemistry

1 answer:

Zina [86]3 years ago

8 0

Answer:

V = 1.66mL acetic acid

Explanation:

dilution formula:

V1*C1 =V2*C2

⇒ V1*(6M) = (100mL)*(0.1M)

⇒ V1 =( (100mL) * (0.1M) ) / (6M)

⇒ V1 = 1.66mL acetic acid

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What is the speed of an electron that has a de Broglie wavelength of 100. nm?

Advocard [28]

Answer: The speed of the electron is $7.24\times 10^3m/s$

Explanation:

To calculate the speed of electron for given wavelength, we use the equation given by De-Broglie's, which is:

$\lambda=\frac{h}{mv}$

where,

$\lambda$ = De-Broglie's wavelength = $100nm=100\times 10^{-9}m$

h = Planck's constant = $6.6\times 10^{-34}Js$

m = mass of the electron = $9.11\times 10^{-31}kg$

v = speed of the electron = ?

Putting values in above equation, we get:

$100\times 10^{-9}m=\frac{6.6\times 10^{-34}Js}{9.11\times 10^{-31}kg\times v}\\\\v=\frac{6.6\times 10^{-34}Js}{9.11\times 10^{-31}kg\times 100\times 10^{-9}m}=7.24\times 10^3m/s$

Hence, the speed of the electron is $7.24\times 10^3m/s$

4 0

3 years ago

If a concentrated solution of acetic acid is 99.5 % HC2 H3 O2 and has a density of 1.05 g/mL, what is the concentration of this

cluponka [151]

Answer:

[CH₃COOH] = 17.4 M

Explanation:

Acetic acid → CH₃COOH

Molar mass → 60 g/mol

99.5% is percent by mass concentration. It means that 99.5 grams of solute are contained in 100g of solution.

Density → 1.05 g/mL. This data is always referred to solution, not solute!.

We determine solution's volume:

1.05 g/mL = 100 g / V → V = 100 g /1.05 g/mL → 95.2 mL

Now we know, that 99.5 g of acetic acid are contained in 95.2 mL

Let's convert to mmoles → 99.5 g / 60 g/mol = 1.66 moles

We convert solution's volume to L → 95.2 mL . 1L / 1000 mL = 0.0952 L

M (mol/L) = 1.66 mol / 0.0952 L = 17.4 M

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3 years ago

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Maurinko [17]

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4 years ago

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victus00 [196]

3p2

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3 years ago

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yKpoI14uk [10]

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3 years ago