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aliya0001 [1]
3 years ago
13

PLEASE HELP FASTTT!!!!

Chemistry
1 answer:
Umnica [9.8K]3 years ago
4 0
I did this when I was younger
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Tanner adds 10 grams of dry sand to 100 milliliters of warm salt water. This mixture is stirred and placed on a table. When Tann
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Based on the diagram below, rank the three objects from least dense to most dense.
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We are not given the diagram needed for this question so it would be better to talk about how to determine which object would be the most dense and least dense. One way to determine this is by looking at the densities of these objects. Higher value means the most dense while the lower value is the opposite.
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Please help me answer this question
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Electrolytes are observed by conductivity - so unknown 2 should be circled, and Tap Water, which almost always contains electrolytes, mineral salts in solution.

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How many grams of hydrogen are needed to produce 1.80g of water according to this equation?
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Answer:

0.2g of hydrogen is needed to produce 1.80g of water

Explanation:

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No. of moles of water$= \frac{Weight}{Molecular \, weight}$ \\

From given values,

Weight of water $=1.80g$

Molecular weight of water $=18g$

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Hence, 0.1 mole of water can be formed from 0.1 mole of $H_{2}$

Now,

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8 0
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Suppose 20.8 g of sodium iodide is dissolved in 250. mL of a 0.70 M aqueous solution of silver nitrate. Calculate the final mola
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Answer:

[Ag+] = [NO3-] = 0.700M

0.555M = [Na+] = [I-]

Explanation:

To solve this question we need to find the moles of sodium iodide, NaI, using its molar mass -. With the moles and the volume we can find the molarity of Na+ and I-. The molarity of the ions of silver nitrate, AgNO3 doesn't change because we are assuming the volume doesn't change:

<em>Molarity Ag⁺ = Molarity NO₃⁻ = 0.700M</em>

<em>Moles NaI -Molar mass: 149.89g/mol-</em>

20.8g NaI * (1mol/149.89g) = 0.0139 moles NaI

<em>Molarity:</em>

0.0139 moles NaI / 0.250L = <em>0.555M = [Na+] = [I-]</em>

7 0
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