Work = (force) x (distance)
You could look at the two cases, and see right away that
the first one has more force acting through more distance,
so it must be more work. But since I just gave you the formula
for Work, let's calculate the amount of it for both cases:
First case: Work = (115 N) x (15 m) = 1,725 joules
Second case: Work = (20 N) x (10 m) = 200 joules
The first case involves 8.625 times as much work as the second case.
The distance from the Sun to the Earth is 149,600,000 km.
B.earth rotates on its axis in 24 hours; i.e., it rotates 15° of longitude per hour.
Answer:
The total distance, side to side, that the top of the building moves during such an oscillation = 31 cm
Explanation:
Let the total side to side motion be 2A. Where A is maximum acceleration.
Now, we know know that equation for maximum acceleration is;
A = α(max) / [(2πf)^(2)]
So 2A = 2[α(max) / [(2πf)^(2)] ]
α(max) = (0.025 x 9.81) while frequency(f) from the question is 0.2Hz.
Therefore 2A = 2 [(0.025 x 9.81) / [((2π(0.2)) ^(2)] ] = 2( 0.245 / 1.58) = 0.31m or 31cm
Explanation:
The problem doesn't specify that the units have to be g/mL, so you can calculate the density in kg/L without converting the mass or volume.
Just make sure that either way, you write the units.
