How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is
1 answer:
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Answer:
k = 52.2 N / m
Explanation:
For this exercise we are going to use the conservation of mechanical energy.
Starting point. When it is 30 m high
Em₀ = K + U = ½ m v² + m g h
Final point. Right when you hit the water
= K_{e} = ½ k x²
in this case the distance the bungee is stretched is 30 m
x = h
as they indicate that there are no losses, energy is conserved
Em₀ = Em_{f}
½ m v² + m g h = ½ k h²
k =
let's calculate
k =
k = 52.2 N / m
To solve this problem we could apply the concepts given by the conservation of Energy.
During the launch given in terms of kinetic energy and reaching the maximum point of the object, the potential energy of the body is conserved. However, part of all this energy is lost due to the work done by the friction force due to friction with the air, therefore
The potential and kinetic energy are conserved and are the same PE = KE and this value is equivalent to 100J, therefore
The kinetic energy will ultimately be less than 100J, so the correct answer is C.