Answer:
1)chest
2)deltoid
3)bicep
4)abs
5)quadriceps
6)lats
7)triceps
8)glutes
9)calves
10)hamstring
11)trapezuis
Explanation:
the explanation is the picture
good luck :)
hopefully, this helps
have a nice day !!
Answer:
4.45×10¯¹¹ N
Explanation:
From the question given above, the following data were obtained:
Mass of ball (M₁) = 4 Kg
Mass of bowling pin (M₂) = 1.5 Kg
Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
Distance apart (r) = 3 m
Force of attraction (F) =?
The force of attraction between the ball and the bowling pin can be obtained as follow:
F = GM₁M₂ / r²
F = 6.67×10¯¹¹ × 4 × 1.5 / 3²
F = 4.002×10¯¹⁰ / 9
F = 4.45×10¯¹¹ N
Therefore, the force of attraction between the ball and the bowling pin is 4.45×10¯¹¹ N
im in flvs too if thats what this is but anyway im doing it right now and i believe it is sunlight was not kept constant
