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sergejj [24]
3 years ago
5

Question is in the picture :,)

Physics
1 answer:
xenn [34]3 years ago
5 0

Answer:

C

Explanation:

When the dwarf planet in the Kuiper belt was discovered, scientists demoted pluto to "dwarf planet" because it was very similar to the other dwarf

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1. On one of the shelves in your physics lab is displayed an antique telescope. A sign underneath the instrument says that the t
Ira Lisetskai [31]

Answer:

a)  f_{e} = 3,375 cm , b)  f₀ = 77.625 cm

Explanation:

The magnification of a telescope is, to see at the far point of vision (infinity image)

        m = - f₀ /  f_{e}

The length of the tube is

        L = f₀ + f_{e}

a) The focal length of the eyepiece

       L = - m  f_{e} +  f_{e}

       L = f_{e} (1-m)

        f_{e} = L / (1-m)

Let's calculate

        f_{e} = 81.0 / (1 - (-23.0)

        f_{e} = 3,375 cm

b) the focal length of the target

       f₀ = -m  f_{e}

       f₀ = 23 (3.68)

       f₀ = 77.625 cm

8 0
3 years ago
The Assignment: A fixed quantity of an ideal gas (R 0.28 kJ/kgK; Cv-0.71kJ/kgK) is expanded from an initial condition of 35 bar,
Nikolay [14]

Answer:

Index of expansion: 4.93

Δu = -340.8 kJ/kg

q = 232.2 kJ/kg

Explanation:

The index of expansion is the relationship of pressures:

pi/pf

The ideal gas equation:

p1*v1/T1 = p2*v2/T2

p2 = p1*v1*T2/(T2*v2)

500 C = 773 K

20 C = 293 K

p2 = 35*0.1*773/(293*1.3) = 7.1 bar

The index of expansion then is 35/7.1 = 4.93

The variation of specific internal energy is:

Δu = Cv * Δt

Δu = 0.71 * (20 - 500) = -340.8 kJ/kg

The first law of thermodynamics

q = l + Δu

The work will be the expansion work

l = p2*v2 - p1*v1

35 bar = 3500000 Pa

7.1 bar = 710000 Pa

q = p2*v2 - p1*v1 + Δu

q = 710000*1.3 - 3500000*0.1 - 340800 = 232200 J/kg = 232.2 kJ/kg

7 0
3 years ago
A leaf falls from a tree. Because the leaf is so light, it will be affected by air
postnew [5]

Answer:

b

Explanation:

7 0
3 years ago
At the _______________ point, the particles in an object have not kinetic energy
Brums [2.3K]
The freezing point ..... :)
4 0
3 years ago
A block rests on a ?at plate that executes vertical simple harmonic motion with a period of 0.58s.
SVETLANKA909090 [29]

Answer:

maximum amplitude  = 0.08 m

Explanation:

Given that

Time period T= 0.58 s

acceleration of gravity g= 9.8 m/s²

We know that time period of simple harmonic motion given as

T = 2π/ω

0.58 = 2π/ω

ω = 10.83rad/s

ω=angular frequency

Lets take amplitude = A

The maximum acceleration given as

a= ω² A

The maximum acceleration should be equal to g ,then block does not separate

a= ω² A

9.8 =  10.83² A

A = 0.08m

maximum amplitude  = 0.08 m

8 0
3 years ago
Read 2 more answers
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