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aleksley [76]
3 years ago
12

Suppose a plot of 1/λ vs f has a slope of 0.728, what is the wave velocity? Give only the numerical answer with 4 decimal place

without units. Answer will be graded to within +/- 0.1 of the correct answer so do not round until the final answer.
Physics
2 answers:
Ganezh [65]3 years ago
4 0
<h2>Answer:</h2>

1.3736

<h2>Explanation:</h2>

The velocity (v) of a wave is given by the product of the frequency (f) and the wavelength (λ) of the wave; i.e

v = fλ           ------------------(i)

Now, the slope of 1/λ vs f implies that;

1/λ is on the vertical axis;

f is on the horizontal axis;

such that the slope s will be given as;

s = 1/λ ÷ f

s = (1/λ) x (1/f)

s = 1/(fλ)     -----------------------(ii)

<em>Since v = fλ from equation (i), substitute this into equation (ii) as follows;</em>

s = 1 / v        -------------------------(iii)

From the question, s = slope = 0.728

<em>Substitute this value of s into equation (iii) as follows;</em>

0.728 = 1 / v

<em>Solve for v;</em>

v = 1 / 0.728

v = 1.3736

Therefore, the wave velocity is 1.3736

Charra [1.4K]3 years ago
3 0

Answer:

The wave velocity is 1.3736

Explanation:

A plot of inverse of wavelength (λ) versus frequency (f), can be analyzed as follows;

The vertical axis will be 1/λ and the horizontal axis will be f

slope = (Δ1/λ)/(Δf)

        = 1/(fλ)

∴ 1/(fλ) = 0.728

From wave equation, V = fλ

where;

V is the wave velocity

f is the frequency of the wave

λ is the wavelength

1/(fλ) = 0.728

1/(V) = 0.728

V = (0.728)⁻¹

V = 1.3736

Therefore, the wave velocity is 1.3736

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Answer:

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Explanation:

Given that,

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f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{0.13\times 10^{-9}}\\\\f=2.30\times 10^{18}\ Hz

So, the frequency of an x-ray is 2.30\times 10^{18}\ Hz. Hence, this is the required solution.

5 0
2 years ago
Suppose that the half-life of an element is 1000 years. How many half-lives will it take before one-eighth of the original sampl
34kurt

Answer:

3

Explanation:

The half-life of a radioactive isotope is the time it takes for the mass of the sample to halve.

This can be rewritten as follows:

m(t) = m_0 (\frac{1}{2})^n

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m(t) is the mass of the sample at time t

m0 is the original mass of the sample

n is the number of half-lives that passed

We see that if we take n=3, the amount of original sample left is

m(t) = m_0 (\frac{1}{2})^3 = m_0 (\frac{1}{8})

So 3 (3 half-lives) is the correct answer.

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The Earth revolves around the Sun once a year at an average distance of 1.50×1011m. Find the orbital radius that corresponds to
DedPeter [7]

Answer:

9.4\cdot 10^{10} m

Explanation:

We can solve the problem by using Kepler's third law, which states that the ratio between the cube of the orbital radius and the square of the orbital period is constant for every object orbiting the Sun. So we can write

\frac{r_a^3}{T_a^2}=\frac{r_e^3}{T_e^2}

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r_o is the distance of the new object from the sun (orbital radius)

T_o=180 d is the orbital period of the object

r_e = 1.50\cdot 10^{11} m is the orbital radius of the Earth

T_e=365 d is the orbital period the Earth

Solving the equation for r_o, we find

r_o = \sqrt[3]{\frac{r_e^3}{T_e^2}T_o^2} =\sqrt[3]{\frac{(1.50\cdot 10^{11}m)^3}{(365 d)^2}(180 d)^2}=9.4\cdot 10^{10} m

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A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle
MAVERICK [17]

Answer:

t₂ = 3.89 s

Explanation:

given,

speed of car  = 23 m/s

speed of motorcycle = 23 m/s

after time of 4 s distance between them is equal to = 53 m

motorcycle accelerates at = 7 m/s

time taken to catch up with car = ?

let t₂ be the time in which motorcycle catches car.

distance traveled by car in t₂ s

d = 23 t₂ + 53

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using equation of motion

s = ut + \dfrac{1}{2}at^2

s = 23 t_2 + \dfrac{1}{2}\times 7 \times t_2^2

now, equating both the distances

23t_2 + 53= 23 t_2 + \dfrac{1}{2}\times 7 \times t_2^2

t_2^2 = 15.143

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time taken by the motorcycle to catch the car is equal to 3.89 s

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