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dusya [7]
3 years ago
15

7. Why does increasing the mass of an egg increase the chance that it will be damaged in a drop?​

Physics
1 answer:
12345 [234]3 years ago
7 0
Because if you increase the surface area of such a fragile object there is more space and in turn more of a chance for the object (in this case the egg) to be damaged.
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Which statement is true about an atom and an element?
Lemur [1.5K]
"<span>An atom is the smallest unit of matter and an element is a pure substance that is made of identical atoms" is correct. Although atoms can be broken down further now, it still take a whole atom to make an element. </span>
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Which components of an atom are found outside of the nucleus
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Electrons are found outside of the nucleus.
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What is special about nitrogen, and what is its main function in the atmosphere
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5 0
3 years ago
If a spring has a spring constant of 1.00 × 10^3 N/m, what is the restoring force when the mass has been displaced 20.0 cm?
never [62]

The spring has a spring constant of 1.00 * 10^3 N/m and the mass has been displaced 20.0 cm then the restoring force is 20000 N/m.

Explanation:

When a spring is stretched or compressed its length changes by an amount x from its equilibrium length then the restoring force is exerted.

spring constant is k = 1.00 * 10^3 N/m

mass is x = 20.0 cm

According to Hooke's law, To find restoring force,

    F = - kx

        = - 1.00 *10 ^3 * 20.0

     F = 20000 N/m

Thus, the spring has a spring constant of 1.00 * 10^3 N/m and the mass has been displaced 20.0 cm then the restoring force is 20000 N/m.

3 0
2 years ago
If a boulder has a weight of 675,000 N what is it’s mass
Anarel [89]

Weight = (mass) x (acceleration of gravity where the object is)

You didn't tell us WHERE the boulder is, so I have to assume that it's on Mars, where the acceleration of gravity is 3.71 m/s².

675,000 N = (mass) (3.71 m/s²)

Mass = (675,000 N) / (3.71 m/s²)

<em>Mass = 181,941 kilograms</em>

The same weight on Earth would suggest a mass of only 68,807 kg, so you can see how important it is to know where you are when you make your measurements.

6 0
3 years ago
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