Answer:
Most likely a mixed acidosis
Explanation:
Mixed acidosis is when you have metabolic acidosis and respiratory acidosis, the concentration of bicarbonate, that must be between 19.1 and 24.7, is 15, so it is below the lesser value. The partial pressure of carbon dioxide should be between 28.3 and 38.7, and client's partial pressure of carbon dioxide is slightly above the upper limit. Finally, pH sould be between 7.39 and 7.47, and client's pH is below the lesser limit. This all means that the blood is too acid.
King Tut's reign came to an end at 3350 years ago
<h3>Further explanation</h3>
Carbon-14 is a radioactive isotope that can decay. This isotope can be used to determine how long ago an organism died by knowing the ratio from 12C to 14C
Can be formulated

Or we can use :

The half-life of C-14, 5730 years, so the decay constant :

Assume the initial C-14 activity was 13.6 disintegrations/min/g of C

Answer:
Specific heat capacity formula
Explanation:
The heat capacity gives the exact heat energy at which a given mass of a substance is heated from one temperature to another.
This formula can help determine how much heat is gained or lost during the reaction and is given by:
Q = mcΔT
where:
Q = heat energy in Joules or Calories
m - mass of the substance (g)
c = Specific heat capacity (J/kg°C)
ΔT = change in temperature = (final temp - initial temp) (°C)
I hope this was helpful.
Answer:
185.05 g.
Explanation
Firstly, It is considered as a stichiometry problem.
From the balanced equation: 2LiCl → 2Li + Cl₂
It is clear that the stichiometry shows that 2.0 moles of LiCl is decomposed to give 2.0 moles of Li metal and 1.0 moles of Cl₂, which means that the molar ratio of LiCl : Li is (1.0 : 1.0) ratio.
We must convert the grams of Li metal (30.3 g) to moles (n = mass/atomic mass), atomic mass of Li = 6.941 g/mole.
n = (30.3 g) / (6.941 g/mole) = 4.365 moles.
Now, we can get the number of moles of LiCl that is needed to produce 4.365 moles of Li metal.
Using cross multiplication:
2.0 moles of LiCl → 2.0 moles of Li, from the stichiometry of the balanced equation.
??? moles of LiCl → 4.365 moles of Li.
The number of moles of LiCl that will produce 4.365 moles of Li (30.3 g) is (2.0 x 4.365 / 2.0) = 4.365 moles.
Finally, we should convert the number of moles of LiCl into grams (n = mass/molar mass).
Molar mass of LiCl = 42.394 g/mole.
mass = n x molar mass = (4.365 x 42.394) = 185.05 g.