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4 years ago

Calculate the frequency in hertz of an x-ray beam with a wavelength of 2.65

Physics

1 answer:

gladu [14]4 years ago

6 0

frequency = speed of light / wavelength = 3 * 10^8/2.65 = 1.13 * 10^8

If the unit of wavelength is in meters, then 1.13 * 10^8 hertz is your answer. If it is in any other unit, you can derive for that one!!!

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A satellite is launched to orbit the Earth at an altitude of 2.90 x10^7 m for use in the Global Positioning System (GPS). Take t

marin [14]

Answer:

$T=66262.4s$

Explanation:

From the question we are told that:

Altitude $A=2.90 *10^7$

Mass $m=5.97 * 10^{24} kg$

Radius $r=6.38 *10^6 m.$

Generally the equation for Satellite Speed is mathematically given by

$V=(\frac{GM}{d} )^{0.5}$

$V=(\frac{6.67*10^{-11}*5.97 * 10^{24}}{6.38 *10^6+2.90 *10^7} )^{0.5}$

$V=3354.83m/s$

Therefore

Period T is Given as

$T=\frac{2 \pi *a}{V}$

$T=\frac{2 \pi *(6.38 *10^6+2.90 *10^7}{3354.83}$

$T=66262.4s$

4 0

3 years ago

What is heat? I need help

emmasim [6.3K]

Something hot like a fire , an eye of a stove , and the sun

4 0

4 years ago

A scientist designed a foam container to help keep frozen foods from melting. Which best explains how the foam works?

FrozenT [24]

I think the answer should be D.<span>It reduces the amount of thermal energy that is transferred from outside to inside the container. </span>

6 0

4 years ago

Read 2 more answers

What is the difference between a 4x100 and a 4x400 relay

qaws [65]

A 4x100 relay is where 4 people run 100 meters and a 4x400 relay is where 4 people run 400 meters

6 0

3 years ago

A(n) 10.1 g bullet is fired into a(n) 2.41 kg ballistic pendulum and becomes embedded in it. The acceleration of gravity is 9.8

fomenos

Answer:

$v = 186.90\,\frac{m}{s}$

Explanation:

The motion of ballistic pendulum is modelled by the appropriate use of the Principle of Energy Conservation:

$\frac{1}{2}\cdot (m_{p}+m_{b})\cdot v^{2} = (m_{p}+m_{b})\cdot g \cdot h$

The final velocity of the system formed by the ballistic pendulum and the bullet is:

$v = \sqrt{2\cdot g\cdot h}$

$v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (0.031\,m)}$

$v\approx 0.78\,\frac{m}{s}$

Initial velocity of the bullet can be calculated from the expression derived of the Principle of Momentum:

$(0.0101\,kg)\cdot v = (2.41\,kg + 0.0101\,kg)\cdot (0.78\,\frac{m}{s} )$

$v = 186.90\,\frac{m}{s}$

5 0

3 years ago