Answer:
In Milgram's experiment, compliance, or doing what the experimenter asked,
the teacher and the learner were in the same room. -C.
The total force that the SUV exerts is:
F = 2000 kg * 3 m/s^2
F = 6000 N
Since a resisting force amounting to 1500 N is exerted,
then the force exerted by the SUV tires is:
F tire = 6000 N – 1500 N
F tire = 4500 N
In order to find which rational number is between 0 and 1, let's convert them into their decimal form:

Looking at the numbers in their decimal form, we can see that the number between 0 and 1 is one-fourth, therefore the correct option is the second one.
Answer: Approximately 3.65 hours
Explanation:
55 km/h x 3.65 hrs = 200.75 Km/h
Complete Question
The complete question is shown on the first uploaded image
Answer:
Explanation:
From he question we are told that
The first mass is 
The second mass is 
From the question we can see that at equilibrium the moment about the point where the string holding the bar (where
are hanged ) is attached is zero
Therefore we can say that

Making x the subject of the formula



Looking at the diagram we can see that the tension T on the string holding the bar where
are hanged is as a result of the masses (
)
Also at equilibrium the moment about the point where the string holding the bar (where (
) and
are hanged ) is attached is zero
So basically


Making
subject

