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ioda
2 years ago
10

Please help i’ll mark you

Physics
2 answers:
suter [353]2 years ago
8 0

Answer:

What should I do. reply quickly for a quick answer

GrogVix [38]2 years ago
3 0

Answer: put a line across the paper

Explanation:

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What do you mean by momentum.Explain​
r-ruslan [8.4K]
Momentum is the quantity of moving motion if that helps in anyway :)
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3 years ago
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True or false. A high gear ratio = more speed = more force.
Tanya [424]

Answer: the answer to your question is

Explanation:

True

Hope this helps✔︎

8 0
3 years ago
a)Show that whennbecomes very large, the energy levels of the hydrogen atom are getting closer to energy.b)Are the rays of these
natali 33 [55]

Answer:

Answered

Explanation:

Energy of electron in  hydrogen atom is given by

E_n= \frac{13.6}{n^2}

now as becomes large

ΔE= E_n+1 - E_n= 18.6 eV(1/n^2- 1/(n+1)^2)

now, as n increases ΔE_n decreases

in the limit n→∞ ,  ΔE_n→0. Thus with increase in n, energy level come close to each other.

b) Since, the wavelength of the rays depends upon the energy level hence they too come closer.

c)Near the ionization threshold the energy level of the atoms come closer and the total energy of the electron becomes almost so that it can be easily removed from the orbit.

5 0
4 years ago
How many neutrons are there in the neutral atom of 20 10Ne? 1. 22 2. 20 3. 12 4. 9 5. 10
vaieri [72.5K]

Answer:

3.) 12

Explanation:

an atomic number is 11 which means this atom will have 11 protons. the atomic mass is 23 which also means 23-11 is 12 neurons.

4 0
3 years ago
Two large metal plates of area 0.7 m2 face each other. They are 5.1 cm apart and have equal but opposite charges on their inner
german

Explanation:

The given data is as follows.

    Area (A) = 0.7 m^{2}.

  Electric field between the plates, (E) = 55 N/C

Since, electric field is related to surface charge density as follows.

          \sigma = \frac{Q}{A}

Also,    E = \frac{\sigma}{\epsilon_{o}}

or,        \sigma = \epsilon_{o} E

Therefore, charge will be calculated as follows.

          Q = \sigma \times A = \epsilon_{o} E \times A

             = 8.854 \times 10^{-12} \times 55 \times 0.7

             = 3.41 \times 10^{-10} C

             = 341 pC

Thus, we can conclude that magnitude of the charge on each plate is 341 pC.

8 0
4 years ago
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