2 years ago

Please help i’ll mark you

Physics

2 answers:

suter [353]2 years ago

8 0

Answer:

What should I do. reply quickly for a quick answer

GrogVix [38]2 years ago

3 0

Answer: put a line across the paper

Explanation:

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Attenuation

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It is called attenuation.

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3 years ago

What is the elastic potential energy of a spring that is compressed a distance of 0.35 m and has a spring constant of 71.8 N/m?

Vitek1552 [10]

Answer:

P.E = 4.398 Joules.

Explanation:

Given the following data;

Spring constant, k = 71.8N/m

Displacement, x = 0.35m

To find the elastic potential energy;

The elastic potential energy of an object is given by the formula;

$P.E = \frac {1}{2}kx^{2}$

Substituting into the equation, we have;

$P.E = \frac {1}{2}*71.8 *(0.35)^{2}$

$P.E = 35.9 * 0.1225$

Elastic potential energy = 4.398 Joules.

<em>Therefore, the elastic potential energy of the spring is 4.398 Joules. </em>

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3 years ago