1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ioda
2 years ago
10

Please help i’ll mark you

Physics
2 answers:
suter [353]2 years ago
8 0

Answer:

What should I do. reply quickly for a quick answer

GrogVix [38]2 years ago
3 0

Answer: put a line across the paper

Explanation:

You might be interested in
Look at the variables for this lab. Which variable would we have to change in order to change the amount of current flowing thro
____ [38]
Where are the variables from the lab?
3 0
2 years ago
Please help fast i need urgent
Sloan [31]
Is there more information ?
5 0
3 years ago
A runner completes the 300-meter dash in 38 seconds. What is the speed of the runner? Round your answer to the nearest tenth.The
Galina-37 [17]
The speed of the runner is 300 m /38 seconds. You can simplify this answer to be about 7.9 m/s
7 0
3 years ago
A ball is thrown upwards at an unknown speed. in a time of
alexandr402 [8]

Answer:

a)  Initial speed of the ball = 14.45 m/s

b) At height 6 m speed of ball = 9.55 m/s

c) Maximum height reached = 10.65 m

Explanation:

a)  We have equation of motion s=ut+\frac{1}{2} at^2, where s is the displacement, u is the initial velocity, t is the time taken and a is the acceleration.

s = 6 m, t = 0.5 seconds, a = acceleration due to gravity value = -9.8m/s^2

 Substituting

    6=u*0.5-\frac{1}{2} *9.8*0.5^2\\ \\ u=14.45m/s

 Initial speed of the ball = 14.45 m/s

 b) We have equation of motion v^2=u^2+2as, where v is the final velocity

   s = 6 m, u = 14.45 m/s, a = -9.8m/s^2

    Substituting

        v^2=14.45^2-2*9.8*6\\ \\ v=9.55m/s

  So at height 6 m speed of ball = 9.55 m/s

c) We have equation of motion v^2=u^2+2as, where v is the final velocity

   u = 14.45 m/s, v =0 , a = -9.8m/s^2

   Substituting

     0^2=14.45^2-2*9.8*s\\ \\ s=10.65 m

  Maximum height reached = 10.65 m

8 0
3 years ago
A 1980-kg car is traveling with a speed of 15.5 m/s. What is the magnitude of the horizontal net force that is required to bring
Dennis_Churaev [7]

Answer: 6067.5 N

Explanation:

Work = Change in Energy. To start, all of the energy is kinetic energy, so find the total KE using: KE = 1/2(m)(v^2). Plug in 1980 kg for m and 15.5 m/s for v and get KE = 237847.5 J.

Now, plug this in for work: Work = Force * Distance; so, divide work by distance to get 6067.5 N.

5 0
3 years ago
Other questions:
  • 1. During mitosis, the genetic material in a cell is replicated, and then the cell splits into two new cells. The two new cells
    11·2 answers
  • 1.Explain frame of reference. How is it different when you are riding inside a car or standing by the highway?
    13·1 answer
  • Plz help........................
    6·1 answer
  • Discuss velocity by providing at least one example and explain why velocity is either a scalar or vector quantity.
    11·2 answers
  • What is the acceleration of a baseball when it is moving downward after being tossed directly upward?
    10·1 answer
  • WILL MARK BRAINLIEST
    8·2 answers
  • A 950 N skydiver jumps from an altitude of 3000 m. What is the total work performed on the skydiver?
    15·1 answer
  • Please, what is a car battery pH?
    5·1 answer
  • An action force is 50 N to the left. The reaction force must be:
    5·2 answers
  • If R1 < R2 < R3, and if these resistors are connected in parallel in a circuit, which one has the greatest voltage drop?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!