<span>D. It shows that the electrons within an atom do not have sharp boundaries.</span>
2H2 (g) + O2 (g) -->2H2 O(g)
mole ratio of H2:O2=2:1
7.25/2=3.625
For the purpose we will here use the ideal gas law:
p×V=n×R×T
V= ?
n = 0.5 moleT= 273.15 K (at STP)
p= 101.325 kPa (at STP)
R is universal gas constant, and its value is 8.314 J/mol×K
Now when we have all necessary date we can calculate the number of moles:
V=nxRxT/p
V=0.5x8.314x273.15/101.325= 11.2 L = 11200 mL
Answer: D.
Answer:
9.9 moles of Ag₂S contain 9.9 moles of sulfur.
Explanation:
Given data:
Number of moles of Ag₂S = 9.9 mol
Number of moles of Sulfur = ?
Solution:
One mole of Ag₂S having 1 mole of sulfur.
In 9.9 moles:
9.9 moles × 1 = 9.9 moles
So 9.9 moles of Ag₂S contain 9.9 moles of sulfur.