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Pachacha [2.7K]
4 years ago
10

Combustion of ethylene glycol leads to a change in internal energy (\DeltaU) of –1189 kJ at 298 K. What is the corresponding cha

nge in enthalpy in kJ\DeltaH? HOCH_2CH_2OH(l) + 5/2 O_2(g) → 2 CO_2(g) + 3 H_2O(l) \DeltaU = –1189 kJ
Chemistry
1 answer:
ddd [48]4 years ago
7 0

Answer:

-1190.24 kJ

Explanation:

The enthalpy change in a chemical reaction that produces or consumes  gases is given by the expression:

ΔH = ΔU + Δngas RT

where  Δn gas is the change of moles of gas, R is the gas constant,and T is temperature.

Now from the given   balanced chemical reaction, the change in number of mol gas is equal to:

Δn gas = mole gas products - mole gas reactants =  2 - 5/2 = -1/2 mol

Sionce we know ΔU and the temperature (298 K), we are in position to calculate the change in enthalpy.

ΔH = -1189 x 10³ J + (-0.5 mol ) 8.314 J/Kmol x 298 K

ΔH = -1.190 x 10⁶ J = -1.190 x 10⁶ J x 1 kJ/1000 J = -1.190 x 10³ J

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The partial pressure of Hydrogen gas can directly be calculated by simply taking the difference of the overall pressure and the vapour pressure of water. That is:

 

P (H2 gas) = 759.2 torr – 23.8 torr

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6 0
4 years ago
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What is exchanged between the system and the surroundings ​
BartSMP [9]

Answer:

see note under explanation

Explanation:

When describing system and surroundings the system is typically defined as the 'object of interest' being studied and surroundings 'everything else'. In thermodynamics heat flow is typically defined as endothermic or exothermic. However, one should realize that the terms endothermic and exothermic are in reference to the 'system' or object of interest being studied. For example if heat is transferred from a warm object to a cooler object it is imperative that the system be defined 1st. So, with that, assume the system is a warm metal cylinder being added into cooler water. When describing heat flow then the process is exothermic with respect to the metal cylinder (the system) but endothermic to the water and surroundings (everything else).

8 0
3 years ago
A pound of margarine costs $1.39. What is the cost of a kilogram of margarine
den301095 [7]

Answer:

              3.064 $

Solution:

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Hence, as given,

                        1 Pound of Margarine costs  =  1.39 Dollars

So,

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Solving for X,

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3 years ago
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Explanation:

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4 years ago
CAN SOMEONE PLEASE HELP?
IgorC [24]

Hey there!:

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Hope that helps!

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