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lana66690 [7]
3 years ago
10

Sodium azide decomposes rapidly to produce nitrogen gas.

Chemistry
1 answer:
brilliants [131]3 years ago
4 0

Answer:

156 g

Explanation:

Let's consider the following reaction.

2 NaN₃(s) → 2 Na(s) + 3 N₂ (g)

We can find the moles of N₂  using the ideal gas equation.

P × V = n × R × T

1.50 atm × 60.0 L = n × (0.08206 atm.L/mol.K) × 305 K

n = 3.60 mol

The molar ratio of N₂ to NaN₃ is 3:2. The moles of NaN₃ are:

3.60 mol N₂ × (2 mol NaN₃ / 3 mol N₂) = 2.40 mol NaN₃

The molar mass of NaN₃ is 65.01 g/mol. The mass of NaN₃ is:

2.40 mol × 65.01 g/mol = 156 g

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\text{ammonia at the final temperature of the mixture. Round your answer to  2 significant digits.}

Answer:

Explanation:

From the correct question above:

The reaction can be represented as:

\mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }

From the above reaction; the ICE table can be represented as:

                    \mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }

I (mol/L)     0.086            0.28                 0              0

C                   -4x                -3x               +2x           +6x

E                 0.086 - 4x     0.28 - 3x      +2x             +6x

At equilibrium;

The water vapor = \dfrac{2.6 \ mol}{100 \ L} = 6x

x = \dfrac{2.6}{100} \times \dfrac{1}{6}

x = 0.00433

\text{equilibrium constant}  ({k_c}) =  \dfrac{ [N_2]^2 [H_2O]^6 }{ [[NH_3]^4] [O_2]^3 }

\implies \dfrac{(2x)^2 (6x)^6}{(0.086-4x)^4\times (0.28-3x)^3} \\ \\

Replacing the value of x, we have:

K_c = \dfrac{4 \times 46,656 \times x^8}{(0.086-4x)^4\times (0.28 -3x)^3} \\ \\ K_c = \dfrac{4 \times 46656 \times (0.00433)^8}{(0.06868)^4(0.26701)^3} \\ \\ K_c = \mathbf{5.4446 \times 10^{-8}}

K_c = \mathbf{5.5 \times 10^{-8} \ to  \ 2 \ significant \ figures}

5 0
3 years ago
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Hello friend ☺

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8 0
3 years ago
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Answer:

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Explanation:

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7 0
3 years ago
If there are 80 liters of argon gas in a piston and the piston expands the gas until its volume is 2000 liters with a pressure o
Mice21 [21]

Answer: The correct answer is A. 11.5 atm. The temperature is held constant at 293 K, therefore, we can use Boyle's Law to determine the initial pressure. Boyle's Law states that there is an inverse relationship between pressure and volume of gases. Therefore, as volume increases, the pressure will decrease and vice versa.

Further Explanation:

Boyle's Law can be mathematically expressed as:

P_{initial}V_{initial}\ = P_{final}V_{final}

In this problem, we are given the values:

P(initial) = ?

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V (final) = 2000 L

Plugging in these values into the equation:

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The initial pressure was 11.5 atm. Since the volume increased or expanded, the space where the gas particles move is bigger, so the frequency of collisions with the wall of the container and with other particles are effectively decreased. This, therefore, decreases the pressure from 11.5 to 0.46 atm.

Learn More

  1. Learn about Charles' Law brainly.com/question/1421697
  2. Learn about Ideal Gas Law brainly.com/question/6534668
  3. Learn about Gay - Lusaac's Law brainly.com/question/1358307

Keywords: gas, Boyle's Law, Ideal Gas Law

7 0
3 years ago
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