1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
madreJ [45]
3 years ago
13

Una pelota rueda por una pendiente con aceleración constante. Cuando pasa por un punto P su velocidad es 1,2 ms-1 y al cabo de u

n breve periodo de tiempo pasa por el punto Q con una velocidad de 2,6 ms-1 .
a. Determine ¿cuál es la velocidad media entre P y Q?
b. Si tarda 1,4s en ir de P a Q, calcule ¿cuál es la distancia PQ?
c. Determine ¿cuál es la aceleración de la pelota entre P y Q?
d. Explicar si la aceleración media en el tramo P y Q es la misma que la calculada en la pregunta c
Physics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Answer:

a) v_{m} = 1.9 m / s , b) x = 2.66 m, c) a = 1 m / s , d)the acceleration is constant the average and instantaneous acceleration is equal

Explanation:

a) The average speed is defined as the average value of the speed in a given interval

        v_{m} = (v1 + v2) / 2

        v_{m} = (1,2 + 2,6) / 2

         v_{m} = 1.9 m / s

b) the distance traveled can be obtained with the average speed

       a = v_{m}  t

       x = 1.9 1.4

       x = 2.66 m

c) to find the acceleration let's use

      v = v₀ + a t

      a = (v- v₀) / t

       a = (2.6 - 1.2) / 1.4

      a = 1 m / s

d) as in the problem they indicate that the acceleration is constant the average and instantaneous acceleration is equal in the case of acceleration variables may not be the same

You might be interested in
A 2500-ohm is connected to a 110v power supply. What is the current through the resistor
Assoli18 [71]

Answer:

0.044 amps

Explanation:

Givens

R = 2500 ohms

E = 110 volts

I = ?

Equation

I = E/R

Solution

I = 110/2500

I = 0.044 amps

7 0
3 years ago
An object that is moving must have a change in A) its speed. B) its position. C) its acceleration. D) its applied force.
denis-greek [22]

An object that's moving doesn't necessarily change its speed or acceleration. Also, the force applied to it doesn't need to change ... in fact, a moving object doesn't need ANY force applied to it in order to keep moving.

But any moving object WILL have a change in its position ... THAT's how you know it's moving, and that's WHY you say "It's moving !". (choice-B)

8 0
3 years ago
A glider with mass 0.24 kg sits on a frictionless horizontal air track, connected to a spring of negligible mass with force cons
shepuryov [24]

Answer:

v=2.556m/s

Explanation:

From the conservation of mechanical energy

K_{E1}+U_1=K_{E2}+U_2

\frac{1}{2}m*v_1^2+\frac{1}{2}*K*x_1^2=\frac{1}{2}m*v_2^2+\frac{1}{2}*K*x_2^2

x_2=0.08m

v_1=0 m/s

Solve to velocity v2

m*v_2^2=k*x_1^2-k*x_2^2

v^2=\frac{k}{m}*(x_1^2-x_2^2)

v^2=\frac{5.5N/m}{0.24kg}*(0.54m^2-0.080^2)

v=\sqrt{6.54m^2/s^2}=2.556m/s

4 0
3 years ago
How much power flows through a circuit with 5 amps and 120 volts?
Ainat [17]
600 watts may be your answer:)
3 0
2 years ago
The position of a particle as it moves along an y axis is given by y = (2.0cm)sin(πt/4), with t in second and y in centimeters.
irina [24]

Part a)

At t = 0  the position of the object is given as

x = 0

At t = 2

x = 2 sin(\pi/2) = 2cm

so displacement of the object is given as

d = 2 - 0 = 2cm

so average speed is given as

v_{avg} = \frac{2}{2} = 1 cm/s

Part b)

instantaneous speed is given by

v = \frac{dy}{dt}

v = 2cos(\pi t/4 ) * \frac{\pi}{4}

now at t= 0

v = \frac{\pi}{2} cm/s

at t = 1

v = 2 cos(\pi/4) * \frac{\pi}{4}

v = \frac{\pi}{2\sqrt2}

at t = 2

v = 0

Part c)

Average acceleration is given as

a_{avg} = \frac{v_f - v_i}{t}

a_{avg} = \frac{0 - \frac{\pi}{2}}{2}

a = -\frac{\pi}{4} cm/s^2

Part d)

Now for instantaneous acceleration

As we know that

a =- \omega^2 y

at t = 0

a = -\frac{\pi^2}{16} * 0 = 0 cm/s^2

at t = 1

y = \sqrt2 cm

now we have

a = -\frac{\pi^2}{16}*\sqrt2

At t = 2 we have

y = 2 cm

a = -\frac{\pi^2}{16}*2

a = -\frac{\pi^2}{8}

<em>so above is the instantaneous accelerations</em>

7 0
3 years ago
Other questions:
  • A 55 kilogram person jumps off a cliff and hits the water 5.8 seconds later, how high is the cliff above the water?
    12·1 answer
  • What do you expect the enclosed current is for a bar magnet?
    6·1 answer
  • In general, metalloids are slightly reactive.
    11·2 answers
  • You generally need a transformer to operate a doorbell because doorbells are designed to work with much smaller voltages than wh
    10·1 answer
  • Points of maximum amplitude on a standing wave are called
    15·1 answer
  • Jenny puts a book on her desk. she lifts the book up with her finger, using a force of 0.5N .The cover is 10cm wide .
    12·1 answer
  • A baseball (A, weight 0.33 lb) moves horizontally at 20 ft/s when it strikes a stationary block (B, weight 10 lb), supported by
    12·1 answer
  • A tugboat is pulling a barge into a harbor. The barge is exerting a force of 3000 N against the tugboat.
    6·2 answers
  • Which model could represent a neutral atom of boron?
    9·2 answers
  • If anyone wants 100 points then come help. I will mark brainlliest. No links just answer
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!