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madreJ [45]
3 years ago
13

Una pelota rueda por una pendiente con aceleración constante. Cuando pasa por un punto P su velocidad es 1,2 ms-1 y al cabo de u

n breve periodo de tiempo pasa por el punto Q con una velocidad de 2,6 ms-1 .
a. Determine ¿cuál es la velocidad media entre P y Q?
b. Si tarda 1,4s en ir de P a Q, calcule ¿cuál es la distancia PQ?
c. Determine ¿cuál es la aceleración de la pelota entre P y Q?
d. Explicar si la aceleración media en el tramo P y Q es la misma que la calculada en la pregunta c
Physics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Answer:

a) v_{m} = 1.9 m / s , b) x = 2.66 m, c) a = 1 m / s , d)the acceleration is constant the average and instantaneous acceleration is equal

Explanation:

a) The average speed is defined as the average value of the speed in a given interval

        v_{m} = (v1 + v2) / 2

        v_{m} = (1,2 + 2,6) / 2

         v_{m} = 1.9 m / s

b) the distance traveled can be obtained with the average speed

       a = v_{m}  t

       x = 1.9 1.4

       x = 2.66 m

c) to find the acceleration let's use

      v = v₀ + a t

      a = (v- v₀) / t

       a = (2.6 - 1.2) / 1.4

      a = 1 m / s

d) as in the problem they indicate that the acceleration is constant the average and instantaneous acceleration is equal in the case of acceleration variables may not be the same

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Two satellites are orbiting earth at different altitudes. Which satellite orbits at a higher speed v around earth? Assume that t
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Answer:

a) the one with a lower orbit    b) the one with a higher  orbit

Explanation:

Let's consider orbital mechanics. To get an object in orbit, we need it to fall to earth parallel to the earth's surface. To understand it easily imagine a projectile thrown horizontally further and further away, at one point, the projectile hits the cannon from behind. Considering there is no wind resistance, that would be a projecile in orbit.

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v = \sqrt{\frac{GM}{r} }

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3 0
3 years ago
Suggest a reason for stirring energy powder in water
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Sea Food is a rich source of ______. *​
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8 0
2 years ago
Read 2 more answers
1. A 930-kg car traveling 56 km/h comes to a complete stop in 2.0 s. What is the
Juli2301 [7.4K]

The force exerted on the car during this stop is 6975N

<u>Explanation:</u>

Given-

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Force, F = ?

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F = 6975N

Therefore, the force exerted on the car during this stop is 6975N

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2 years ago
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