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Gnom [1K]
3 years ago
8

Explain how energy that comes from the outside of the Earth system drives the flow of water on surface currents.

Physics
1 answer:
horrorfan [7]3 years ago
4 0

Answer:

The ocean and atmosphere are connected. They work together to move heat and fresh water across the globe. Wind-driven and ocean-current circulations move warm water toward the poles and colder water toward the equator. ... The majority of the thermal energy at the Earth's surface is stored in the ocean.

Explanation:

The ocean and atmosphere are connected. They work together to move heat and fresh water across the globe. Wind-driven and ocean-current circulations move warm water toward the poles and colder water toward the equator. ... The majority of the thermal energy at the Earth's surface is stored in the ocean.

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What is wireless electricity​
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Answer:

Transfer of electricity without wire , is known as wireless electricity.

Sir Nicola Tesla came up with this concept.

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3 years ago
Subtract the following numbers, using scientific notation and the correct number of significant digits.
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Answer:

The correct answer is - 6.49 × 10^3 mm.

Explanation:

The correct scientific notation of the given subtraction problem is:

6.94 × 10^3 mm - 4.5 × 10^2 mm = _____.

The correct number of significant digits is

a. 6.94 × 10^3 mm = 3

b. 4.5 × 10^2 mm = 2

So subtracting the 6.94 × 10^3 mm - 4.5 × 10^2 mm

= 6940 - 450

= 6.49× 10^3 mm.

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Anything that moves up and down or back and forth in a rhythmic way is vibrating true false
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What is the equivalent capacitance of the three capacitors in the figure (figure 1)?
vekshin1

The equivalent capacitance of the combination is  \dfrac{1}{C} = \dfrac{1}{C_1}+\dfrac{1}{C_2}  where C1 and C2 are the capacitance of both capacitors in series.

<h3>What is equivalent capacitor?</h3>

Let the capacitance of both capacitors be C1 and C2. For a series connected capacitors, same charge flows through the capacitors but different voltage flows through them.

Let Q be the amount of charge in each capacitors,

V be the voltage across each capacitors

C be the capacitance of the capacitor.

Using the formula Q = CV where V = Q/C... (1)

For the large capacitor with capacitance of the capacitor C1,

Q = C_1V_1;

V_1 = \dfrac{Q}{C_1}...(2)

where V_1 is the voltage across C_1,

For the small capacitor with capacitance of the capacitor C_2,

Q = C_2V_2;

V_2 = \dfrac{Q}{C_2} ... (3)

where V_2 is the voltage across C_2,

Total voltage V in the circuit will be;

V = V_1+V_2... (4)

Substituting equation 1, 2 and 3 in equation 4, we have;

\dfrac{Q}{C} = \dfrac{Q}{C_1} +\dfrac{ Q}{C_2}

\dfrac{Q}{C} = Q({\dfrac{1}{C_1}+\dfrac{1}{C_2})

Since change Q is the same for both capacitors since they are in series, they will cancel out to finally have;

\dfrac{1}{C} = ({\dfrac{1}{C_1}+\dfrac{1}{C_2})

This gives the equivalent capacitance of the combination.

To know more about equivalence capacitance follow

brainly.com/question/5626146

#SPJ4

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