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enyata [817]
3 years ago
7

Physical isolation of atrial muscle cells from ventricular muscle cells is a function of which of the following?

Physics
1 answer:
solong [7]3 years ago
5 0

Answer:

The cardiac skeleton

Explanation:

The cardiac skeleton is not a "true" skeleton, but it provides structure and support for the heart, as well as isolating the atrial muscle cells from ventricular muscle cells.

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What is the order of magnitude of the gravitational force between two 1.0 kilogram charges that are positioned 1.0 meter apart?
stiks02 [169]

The answer is  -11

Enjoy!

6 0
3 years ago
A 25kg mass is suspended at the end of a horizontal, massless rope that extends from a wall on the left and from the end of a se
patriot [66]
<h2>Answer:20.97g N,32.63g N</h2>

Explanation:

We consider the forces at the knot.

The vertical forces are

T_{2}Sin(50^{0}}) is the vertical component of tension T_{2} at the knot.

-25g is the weight of the mass 25Kg acting downwards.

The horizontal forces are

-T_{1} is the tension in the rope acting left.

T_{2}Cos(50^{0}) is the horizontal component of tension T_{2} acting towards right.

Since the knot has no mass,it is always in equilibrium.

So,the sum of forces acting on it will be zero.

Balancing vertical forces gives,

T_{2}Sin(50^{0}})-25g=0

T_{2}=32.63gN

Balancing horizontal forces gives,

T_{2}Cos(50^{0})-T_{1}=0

T_{1}=32.63g\times Cos(50^{0})=20.97gN

7 0
3 years ago
Read 2 more answers
What is the period of a spring that oscillates with a frequency of 2.09 Hz​
Sergio [31]

Frequency, υ = 2.09 Hz

We know that time period, T = 1/υ

∴ T = 1 ÷ 2.09

⇒ T = 0.4784 seconds

5 0
4 years ago
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Please show all the steps and work. The answer is -3.9 m/s2
konstantin123 [22]

Given that,

Initial velocity of the airplane = 66 m/s

Distance = 560 m

Final velocity of the airplane = 0 (stops)

To find,

Acceleration of the airplane.

Solution,

Let us consider that a is the acceleration of the airplane. We can find it using third equation of motion as follows :

v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{0^2-66^2}{2(560)}\\\\a=-3.9\ m/s^2

Therefore, the acceleration of the airplane is -3.9\ m/s^2

8 0
3 years ago
A device consisting of four heavy balls connected by low-mass rods is free to rotate about an axle. It is initially not spinning
zubka84 [21]

The angular speed of the device is 1.03 rad/s.

<h3>What is the conservation of angular momentum?</h3>

A spinning system's ability to conserve angular momentum ensures that its spin will not change until it is subjected to an external torque; to put it another way, the rotation's speed will not change as long as the net torque is zero.

Using the conservation of angular momentum

L_{i}=L_{f}

Here,  = the system's angular momentum before the collision

L_{i} = 0 + mv

= (0.005)(450)(0.752)

= 1.692 kgm²/s

The moment of inertia of the system is given by

I = 2(M₁R₁² + M₂R₂²)+ mR₁²

= 2[(1.2)(0.8)² +(0.5)(0.3)²]+0.005(0.8)²

= 1.6292 kgm²

Here,  = Iω

So,

1.692 = 1.6292(ω)

ω = 1.03 rad/s

To know more about the conservation of angular momentum, visit:

brainly.com/question/1597483

#SPJ1

4 0
1 year ago
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