<h2>
Answer:20.97g N,32.63g N</h2>
Explanation:
We consider the forces at the knot.
The vertical forces are
is the vertical component of tension
at the knot.
is the weight of the mass
acting downwards.
The horizontal forces are
is the tension in the rope acting left.
is the horizontal component of tension
acting towards right.
Since the knot has no mass,it is always in equilibrium.
So,the sum of forces acting on it will be zero.
Balancing vertical forces gives,


=
Balancing horizontal forces gives,



Frequency, υ = 2.09 Hz
We know that time period, T = 1/υ
∴ T = 1 ÷ 2.09
⇒ T = 0.4784 seconds
Given that,
Initial velocity of the airplane = 66 m/s
Distance = 560 m
Final velocity of the airplane = 0 (stops)
To find,
Acceleration of the airplane.
Solution,
Let us consider that a is the acceleration of the airplane. We can find it using third equation of motion as follows :

Therefore, the acceleration of the airplane is 
The angular speed of the device is 1.03 rad/s.
<h3>What is the conservation of angular momentum?</h3>
A spinning system's ability to conserve angular momentum ensures that its spin will not change until it is subjected to an external torque; to put it another way, the rotation's speed will not change as long as the net torque is zero.
Using the conservation of angular momentum

Here, = the system's angular momentum before the collision
= 0 + mv
= (0.005)(450)(0.752)
= 1.692 kgm²/s
The moment of inertia of the system is given by
I = 2(M₁R₁² + M₂R₂²)+ mR₁²
= 2[(1.2)(0.8)² +(0.5)(0.3)²]+0.005(0.8)²
= 1.6292 kgm²
Here, = Iω
So,
1.692 = 1.6292(ω)
ω = 1.03 rad/s
To know more about the conservation of angular momentum, visit:
brainly.com/question/1597483
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