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3 years ago

13. Which of the following is considered to be a vector?

Physics

2 answers:

kompoz [17]3 years ago

8 0

B velocity hope it helps

katrin [286]3 years ago

7 0

Answer:

B.) Velocity

Explanation:

A vector is a mathematical object that has a size, called the magnitude, and a direction. For example, a vector would be used to show the distance and direction something moved in.

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A positive point charge (q = +8.65 x 10-8 C) is surrounded by an equipotential surface A, which has a radius of rA = 2.97 m. A p

ella [17]

Answer:

$r_B = 1.88 m$

Explanation:

As we know that work done by electric force is given as

$W_e = -q\Delta V$

so here we know that charge is moving from

$r_A = 2.97 m$

to another position

so we will have

$W_{AB} = \frac{kq_1q_2}{r_A} - \frac{kq_1q_2}{r_B}$

$-6.95\times 10^{-9} = (9\times 10^9)(8.65\times 10^{-8})(4.56\times 10^{-11})(\frac{1}{2.97} - \frac{1}{r_B})$

$-0.196 = (\frac{1}{2.97} - \frac{1}{r_B})$

$r_B = 1.88 m$

7 0

3 years ago

Frick and Frack are standing back-to-back, leaning on each other, but not moving. If Frick weighs

mylen [45]

Answer:

Frick is pushing harder

Explanation:

if Frack weighs more and he was pushing harder they would be moving, but if Frick pushes harder then they wont move

7 0

2 years ago

Read 2 more answers

When the top right-hand capacitor is filled with a material of dielectric constant κ, the charge on this capacitor is increases

Olin [163]

Answer: k = 2.07692

Explanation: Please find the attached files for the solution

6 0

3 years ago

Read 2 more answers

A 19 nC charge is moved in a uniform electric field. The electric field does 5.3 μJ of work as the charge moves from point A to

Marizza181 [45]

Answer:

The potential difference between points A and B is 278.95 volts.

The potential difference between points B and C is -642.10 volts.

The potential difference between points A and C is -363.15 volts.

Explanation:

Given :

Charge of the particle, q = 19 nC = 19 x 10⁻⁹ C

Work is done to move a charge from point A to B, W₁ = 5.3 μJ

Work done to move a charge from point B to C, W₂ = -12.2 μJ

Let V₁ be the potential difference between point A and B, V₂ be the potential difference between point B and C and V₃ be the potential difference between point A and C.

The relation between work done and potential difference is:

W = qV

V = W/q ....(1)

Using equation (1), the potential difference between points A and B is:

$V_{1}=\frac{W_{1} }{q}$