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ExtremeBDS [4]
2 years ago
15

A baseball is thrown at an angle of 22◦ relative to the ground at a speed of 24.8 m/s. The ball is caught 43.5518 m from the thr

ower. The acceleration due to gravity is 9.81 m/s^2
How long is it in the air?
Answer in units of s.
How high is the tallest spot in the ball’s path?
Answer in units of m
Physics
1 answer:
sveta [45]2 years ago
7 0

Answer:

12 seconds in the air

2.5

very high

132

Explanation:

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Vaselesa [24]

Answer:

its b

Explanation:

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2 years ago
Read 2 more answers
Question 3 of 15
omeli [17]

Answer:

B) Degrees

Explanation:

The directions of the vectors are often defined in terms of due East, due North, due West and due South. A direction exactly in between of North and East can be described as Northeast, similarly we can describe directions in terms of Northwest, Southeast and South west.

From these, the direction of a vector can be easily expressed in degrees, which is measured counter clockwise about its tail from due East. Considering that we can say that East is at 0° , North is at 90° , West is at 180 and South is at 270° counter clockwise rotation from due East.

So, we know that the direction of a vector lying somewhere between due East i.e 0° and due North i.e 90°, will be measured in degrees, which will have a value between 0°-90°

4 0
2 years ago
A crane does 300 Joules of work in 6 seconds. How much power was used?
HACTEHA [7]

Answer: P= mad/t or P=w/t so P= 300/6= 50 W

6 0
2 years ago
7) T F If two forces of equal magnitude act on an object that is hinged at a pivot, the force acting farther from the pivot must
saul85 [17]

Answer:

False

Explanation:

The torque exerted by a force is given by:

\tau=Fd sin \theta

where

F is the magnitude of the force

d is the distance between the point of application of the force and the pivot

\theta is the angle between the directions of F and d

We see that the magnitude of the torque depends on 3 factors. In this problem, we have 2 forces of equal magnitude (so, equal F). Moreover, one of the forces (let's call it force 1) acts farther from the pivot than force 2, so we have

d_1 > d_2

However, this does not mean that force 1 produces a greater torque. In fact, it also depends on the angle at which the force is applied. For instance, if the first force is applied parallel to d, then we have

\theta_1 =0\\sin \theta=0

and the torque produced by this force would be zero.

So, the statement is false.

4 0
3 years ago
A large helium filled balloon is used as the center piece for a graduation party. The balloon alone has a mass of 225 kg and it
Orlov [11]

To solve this problem it is necessary to apply the concepts related to Newton's second law, the definition of density and sum of forces in bodies.

From Newton's second law we understand that

F= ma (\rightarrow Gravity at this case)

Where,

m = mass

a= acceleration

Also we know that

\rho = \frac{m}{V} \Rightarrow m = \rho V

Part A) The buoyant force acting on the balloon is given as

F_b = ma

As mass is equal to the density and Volume and acceleration equal to Gravity constant

F_b = \rho V g

F_b = 1.2*323*9.8

F_b = 3798.5

PART B) The forces acting on the balloon would be given by the upper thrust force given by the fluid and its weight, then

F_{net} = F_b -W

F_{net} = F_b -(mg+\rho_H Vg)

F_{net} = 3798.5-(9.8*225*9.8*0.179*323)

F_{net} = 1030N

PART C) The additional mass that can the balloon support in equilibrium is given as

F_{net} = m' g

m' =\frac{F_{net}}{g}

m' = \frac{1030}{9.8}

m' = 105Kg

4 0
3 years ago
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