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Assoli18 [71]
3 years ago
5

A large truck breaks down out on the road and receives a push back to town by a small compact car.

Physics
1 answer:
Anton [14]3 years ago
5 0

Answer:

A True. It agrees with Newton's third law

3 True. The car pushes the truck and goes at constant speed

Explanation:

To examine the final answers, we must silver the solution of the problem, if we see Newton's third law, action and reaction, we see that the car pushes the truck the action, the truck must oppose this force with a force applied on the car of equal magnitude, but opposite direction

In view of the above, let's review the statements.

A True. It agrees with Newton's third law

B False. Violate Newton's third law

C False  violate Newton´s third law

D False. The force is exerted by the car not specifically by the engine

E Faults if no force is exerted the truck should stop due to friction

Second question

If the two vehicles move at the same speed, the resulting force on each of them must be zero

1 False. If the truck doesn't get nine, it can't go at cruising speed

2 False if the car is accelerating it cannot go at constant speed

3 True. The car pushes the truck and goes at constant speed

4 False. If the truck slows it should slow down

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Matter is anything that has mass and takes up space. Which units of measurement can you use to describe these two properties?
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3 years ago
Two physics students are standing on skateboards and facing each other. Their masses, including the skateboards, are 95 kg and 5
andrey2020 [161]

Answer:

1) \sum \vec p=0\ kg.m.s^{-1}

2) v_2=55.078\ m.s^{-1}

Explanation:

Given:

  • mass of heavier student, m_1=95\ kg
  • mass of lighter student, m_2=58\ kg
  • velocity of the heavier student after the mutual push, v_1=3.1\ m.s^{-1}

1)

Since they push each other and we are neglecting any friction that means we can consider this as a perfectly elastic collision. So the momentum of the two bodies will be equal and in opposite direction.

Since momentum is a vector quantity so the total momentum of the system as a whole will be zero.

2)

<u>From the condition of elastic collision:</u>

p_1=p_2

m_1.v_1=m_2.v_2

95\times 3.1=58\times v_2

v_2=55.078\ m.s^{-1}

6 0
4 years ago
a foul ball is hit into the stands at a baseball game. the ball rises to a height of 38 meters and is caught on its way down by
lisov135 [29]

The velocity of the ball when it was caught is 12.52 m/s.

<em>"Your question is not complete it seems to be missing the following, information"</em>,

find the velocity of the ball when it was caught.

The given parameters;

maximum height above the ground reached by the ball, H = 38 m

height above the ground where the ball was caught, h = 30 m

The height traveled by the ball when it was caught is calculated as follows;

y = H - h

y = 38 - 30 = 8 m

The velocity of the ball when it was caught is calculated as;

v_f^2 = v_0 + 2gh\\\\v_f^2 = 0 + (2\times 9.8 \times 8)\\\\v_f^2 = 156.8\\\\v_f = \sqrt{156.8} \\\\v_f = 12.52 \ m/s

Thus, the velocity of the ball when it was caught is 12.52 m/s.

Learn more here: brainly.com/question/14582703

4 0
3 years ago
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