All categories

3 years ago

A 0.610 m aqueous solution of kbr has a total mass of 75.0 g. what masses of solute and solvent are present?

1 answer:

8 0

To determine the masses of each component, we need to know the concentration first in terms of molality which is mol per mass of solution. Assuming the density of the solution is equal to that of water we would find:

molality = 0.160 mol KBr / L ( 1 L / 1 kg solution ) = 0.160 mol KBr / kg solution

mass KBr = 0.160 mol KBr / kg solution (.0750 kg solution ) ( 119 g KBr / mol KBr ) = 1.428 g KBr

mass solvent = 75 - 1.428 = 73.572 g water

You might be interested in

Why is O2 necessary for rusting?

Charra [1.4K]

O2 isn't necessary for rusting, but some source of oxygen is required. Rust is just another name for iron oxide, and without oxygen there can't be oxide.

Hope this helps,

Davinia.

5 0

3 years ago

Read 2 more answers

1. List the seasons from longest to shortest, including the number of days in each season.

GenaCL600 [577]

Search it up bro it’s on the internet lol

4 0

3 years ago

In case of accidental contact with chemicals, how long should the eyes be flushed at the eyewash station

FromTheMoon [43]

Answer:

See the answer below

Explanation:

<em>The duration of flushing the eyes at the eyewash station in case of accidental contact with chemicals depends of the nature of the chemical.</em>

If the chemical is known to be a <u>non-irritant or mild-irritant</u> one, a <u>5-minute </u>washing time is recommended as the first aid. before seeking the help of a physician,

For <u>moderate to severe irritant</u> chemicals, an immediate <u>15-20 minutes</u> washing period is recommended before seeking further medical help.

For <u>corrosive and strong alkalis</u> chemicals, <u>30 and 60 minutes</u> washing are recommended respectively before seeking the attention of a physician.

However, if the nature of the chemical is unknown,<u> a minimum of 20-minutes washing is generally recommended</u> as first aid before seeking immediate medical help.

6 0

2 years ago

If 65.5 moles of an ideal gas is at 9.15 atm at 50.30 °C, what is the volume of the gas?

qwelly [4]

To calculate for the volume, we need a relation to relate the number of moles (n), pressure (P), and temperature (T) with volume (V). For simplification, we assume the gas is an ideal gas. So, we use PV=nRT.

PV = nRT where R is the universal gas constant
V = nRT / P
V = 65.5 ( 0.08205 ) (273.15 + 50.30) / 9.15
V = 189.98 L

7 0

3 years ago

I NEED HELP ASAP! PLEASE BE GENUINE

love history [14]

1. The molar mass of the unknown gas obtained is 0.096 g/mol

2. The pressure of the oxygen gas in the tank is 1.524 atm

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

<h3>1. How to determine the molar mass of the gas </h3>

Rate of unknown gas (R₁) = 11.1 mins
Rate of H₂ (R₂) = 2.42 mins
Molar mass of H₂ (M₂) = 2.02 g/mol

Molar mass of unknown gas (M₁) =?

R₁/R₂ = √(M₂/M₁)

11.1 / 2.42 = √(2.02 / M₁)

Square both side

(11.1 / 2.42)² = 2.02 / M₁

Cross multiply

(11.1 / 2.42)² × M₁ = 2.02

Divide both side by (11.1 / 2.42)²

M₁ = 2.02 / (11.1 / 2.42)²

M₁ = 0.096 g/mol

<h3>2. How to determine the pressure of O₂</h3>

From the question given above, the following data were obtained:

Volume (V) = 438 L
Mass of O₂ = 0.885 kg = 885 g
Molar mass of O₂ = 32 g/mol
Mole of of O₂ (n) = 885 / 32 = 27.65625 moles
Temperature (T) = 21 °C = 21 + 273 = 294 K
Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

The pressure of the gas can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

Divide both side by V

P = nRT / V

P = (27.65625 × 0.0821 × 294) / 438

P = 1.524 atm

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

Learn more about ideal gas equation:

brainly.com/question/4147359

6 0

2 years ago