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arsen [322]
2 years ago
6

Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweez

ers is 1000 W/m2, the same as the intensity of sunlight at the surface of the Earth.
Required:
a. What is the pressure on an atom if light from the tweezers is totally absorbed? ?
b. If this pressure were exerted on a tritium atom, what would be its acceleration?
Physics
1 answer:
WITCHER [35]2 years ago
7 0

Answer:

Explanation:

a )

If it is totally absorbed pressure is calculated as follows .

Pressure = I / c where I is intensity of light falling .

= 1000 / 3 x 10⁸

= 3.33 x 10⁻⁶ N / m²

b ) weight of tritium atom

=  3 x 1.67 x 10⁻²⁷ kg

acceleration = force / mass

=    3.33x 10⁻⁶ / 3 x 1.67 x 10⁻²⁷

= .6646 x 10²¹ m /s²

= 66.46 x 10¹⁹ m / s²

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One end of an insulated metal rod is maintained at 100 ∘C and the other end is maintained at 0.00 ∘C by an ice–water mixture. Th
lozanna [386]

Answer:

k=105.0359\times 10^4\,W.m^{-1}.K^{-1}

Explanation:

Given:

temperature at the hotter end, T_H=100^{\circ}C

temperature at the cooler end, T_C=0^{\circ}C

length of rod through which the heat travels, dx=0.7\,m

cross-sectional area of rod, A=1.1\times 10^{-4}\,cm^2

mass of ice melted at zero degree Celsius, m=8.7\times 10^{-3}\,kg

time taken for the melting of ice, t=15\times60=900\,s

thermal conductivity k=?

By Fourier's Law of conduction we have:

\dot{Q}=k.A.\frac{dT}{dx}......................................(1)

where:

\dot{Q}=rate of heat transfer

dT= temperature difference across the length dx

Now, we need the total heat transfer according to the condition:

we know the latent heat of fusion of ice,  L = 334000\,J.kg^{-1}

Q=m.L

Q=8.7\times 10^{-3}\times 334000

Q=2905.8\,J

Now the heat rate:

\dot{Q}=\frac{Q}{t}

\dot{Q}=\frac{2905.8}{900}

\dot{Q}=3.2287\,W

Now using eq,(1)

3.2287=k\times 1.1\times 10^{-4} \times \frac{100}{0.7}

k=205.4606\,W.m^{-1}.K^{-1}

8 0
3 years ago
An airplane in a holding pattern flies at constant altitude along a circular path of radius 3.38 km. If the airplane rounds half
Andrej [43]

Answer:

a) 6076 m

b) 43.33 m/s

c) 68 m/s

Explanation:

(a) If the airplane rounds half the circle in 156s, its displacement is the circle diameter in 156s, or twice the circle's radius

s = 2r = 2* 3.38km = 6.76 km or 6760 m

(b) The average velocity would be displacement over unit of time

v = s/t = 6760 / 156 = 43.33 m/s

(c) The length of the chord it's swept in 156s is half of the circle perimeter

c = πr = π3.38 = 10.62 km or 10620 m

The airplane average speed is its chord length over a unit of time

c / t = c / 156 = 68 m/s

4 0
2 years ago
What is the kinetic energy of a 145 g baseball moving at 42 m/s?
klio [65]
Answer:
Kinetic energy = 127.89 Joules

Explanation:
Kinetic energy is calculated using the following rule:
KE = (1/2)*v* v^2
Where:
m is the mass = 145 g = 0.145 kg
v is the velocity = 42 m/sec

Substitute in the above equation to get the kinetic energy as follows:
KE = (0.5)(0.145)(42)^2
Kinetic energy = 127.89 Joules

Hope this helps :)
8 0
3 years ago
The plates of a parallel-plate capacitor are 700 cm2 in area and 0.3 cm apart. The potential difference between the plates is 93
Kisachek [45]

Answer: a) E = 311,666.7 V/m, b) q = 1.54×10^-10c, c) F = 4.799×10^-5 N, d) 0.0629 J

Explanation:

Area = 700cm² = (700/100)² = 7² = 49m²

Distance between plates (d) = 0.3cm = 0.3/100 = 0.003 m

V = potential difference = 935v

A)

Recall that for a capacitor that V = Ed

Where E = strength of electric field.

935 = E× 0.003

E = 935/ 0.003

E = 311,666.7 V/m

B)

C =qV

Where q = magnitude of charge on capacitor.

We need to get the value for C before we can get for q.

C =ε0×A/d

Where ε0 =permittivity of free space = 8.85×10^-12

Hence we have that

C = 8.85×10^-12 × 49/ 0.003

C = 4.32×10^-10/0.003

C = 1.44×10^-7 F

But C=qV

1.44×10^-7 = q (935)

q = 1.54×10^-10c

C)

F=Eq

Where E = strength of electric field = 311,666.7 V/m, q = 1.54×10^-10c

F = 311,666.7 × 1.54×10^-10

F = 4.799×10^-5 N

D)

Total energy stored = cv²/2

Total energy = 1.44×10^-7 × 935²/2

Total energy = 0.0629 J

4 0
2 years ago
Susan makes the following entry in her notebook: “On Friday we were given a blue liquid in a shallow container. We placed it on
Nat2105 [25]

Answer:

Explanation:

a. From the information provided in the question, the blue liquid is a solution. This is because a solution is a type of homogeneous mixture (that has an evenly distributed solute in a solvent) which is the reason the liquid was said to be blue (and not immiscible blue solid in a liquid) but after been exposed to heat became just a blue solid. Typically, a solution has a solute and a solvent (combined), the solute here is the blue solid while the solvent is the liquid that made the combination a liquid.

b. Since the dish containing the liquid was placed on a windowsill, it can be assumed that the dish was subjected to heat from the sun which caused the liquid (in the solution) to evaporate after exposure to the heat from the sun (over the weekend) leaving the blue solid solute (of the solution) to remain in the dish. This can be referred to as evaporation to dryness in separation techniques (if the goal was to intentionally separate the solid solute from the liquid solvent).

4 0
2 years ago
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