Ask question

Ask question

All categories

3 years ago

6

Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweez

ers is 1000 W/m2, the same as the intensity of sunlight at the surface of the Earth.
Required:
a. What is the pressure on an atom if light from the tweezers is totally absorbed? ?
b. If this pressure were exerted on a tritium atom, what would be its acceleration?

1 answer:

WITCHER [35]3 years ago

7 0

Answer:

Explanation:

a )

If it is totally absorbed pressure is calculated as follows .

Pressure = I / c where I is intensity of light falling .

= 1000 / 3 x 10⁸

= 3.33 x 10⁻⁶ N / m²

b ) weight of tritium atom

= 3 x 1.67 x 10⁻²⁷ kg

acceleration = force / mass

= 3.33x 10⁻⁶ / 3 x 1.67 x 10⁻²⁷

= .6646 x 10²¹ m /s²

= 66.46 x 10¹⁹ m / s²

You might be interested in

A circular-motion addict of mass 82.0 kg rides a Ferris wheel around in a vertical circle of radius 10.0 m at a constant speed o

alisha [4.7K]

Answer:

(a) Time period is 8.85 s

(b) Normal force at the highest point is 390.2 N

(c) Normal force at the lowest point is 1217 N

Explanation:

Given:

Mass of person, m = 82.0 kg

Radius of the wheel, r = 10.0 m

Speed of the wheel, v = 7.10 m/s

(a) Time period of the circular motion is determine by the relation:

$T=\frac{2\pi r}{v}$

Substitute the suitable values in the above equation.

$T=\frac{2\pi\times10 }{7.10}$

T = 8.85 s

(b) The normal force ( F ) at the highest point of the circular path is given by the relation:

F = F₁ - F₂ ....(1)

Here F₁ is gravitational downward force acting on the person and F₂ is the centripetal force.

Gravitational Force, F₁ = mg

Here g is acceleration due to Earth's gravity.

Centripetal force, F₂ = mv²/r

Thus, the equation (1) becomes:

$F=mg-\frac{mv^{2} }{r}$

Substitute the suitable values in the above equation.

$F=82\times9.8-\frac{82\times7.10^{2} }{10}$

F = 390.2 N

(c) The normal force ( F ) at the lowest point of the circular path is given by the relation:

F = F₁ + F₂ ....(2)

Here F₁ is gravitational downward force acting on the person and F₂ is the centripetal force.

Thus the equation (2) becomes:

$F=mg+\frac{mv^{2} }{r}$

$F=82\times9.8+\frac{82\times7.10^{2} }{10}$

F = 1217 N

8 0

3 years ago

Trolley A has a mass of 2kg and is moving at 2m/s. It collides with trolley B, which has the same mass but is stationary. What i

Aleksandr-060686 [28]

Assuming your two trolleys stick together after the collision, your momentum equation would be M1V1+M2V2=(M1+M2)V3 and since V2 is 0, then 2x2=(2+2)V3, thereore the final velocity would be 1, wich would make the final momentum 4

5 0

4 years ago

Nan investigated how many students at her high school had summer jobs. Which of the following is the procedure of her investigat

aalyn [17]

<span>In order to answer her question regarding how many students at her high school had summer jobs Nan must follow the procedure given in answer option B: First, randomly select 100 students, then ask them if they have summer jobs. In statistics this method is known as Population Sampling. These 100 students are chosen at random in order to avoid bias - we need them to be representative of the entire high school population.</span>

7 0

3 years ago

g Two cars, car 1 and car 2 are traveling in opposite directions, car 1 with a magnitude of velocity v1=13.0 m/s and car 2 v2= 7

bogdanovich [222]

Answer:

When they are approaching each other

$f_a = 2228.7 \ Hz$

When they are passing each other

$f_a = 2100Hz$

When they are retreating from each other

$f_a = 1980.7 Hz$

Explanation:

From the question we are told that

The velocity of car one is $v_1 = 13.0 m/s$

The velocity of car two is $v_2 = 7.22 m/s$

The frequency of sound from car one is $f_e = 2.10 kHz$

Generally the speed of sound at normal temperature is $v = 343 m/s$

Now as the cars move relative to each other doppler effect is created and this can be represented mathematically as

$f_a = f_o [\frac{v \pm v_o}{v \pm v_s} ]$

Where $v_s$ is the velocity of the source of sound

$v_o$ is the velocity of the observer of the sound

$f_o$ is the actual frequence

$f_a$ is the apparent frequency

Considering the case when they are approaching each other

$f_a = f_o [\frac{v + v_o}{v - v_s} ]$

$v_o = v_2$

$v_s = v_1$

$f_o = f_e$

Substituting value

$f_a = 2100 [\frac{343 + 7.22}{ 343 - 13} ]$

$f_a = 2228.7 \ Hz$

Considering the case when they are passing each other

At that instant

$v_o = v_s = 0m/s$

$f_o = f_e$

$f_a = f_o [\frac{v }{v } ]$

$f_a = f_o$

Substituting value

$f_a = 2100Hz$

Considering the case when they are retreating from each other

$f_a = f_o [\frac{v - v_o}{v + v_s} ]$

$v_o = v_2$

$v_s = v_1$

$f_o = f_e$

Substituting value

$f_a = 2100 [\frac{343 - 7.22}{343 + 13} ]$

$f_a = 1980.7 Hz$

7 0

4 years ago

A series circuit that is connected to a 50 V, 60 Hz source is made up of 25 ohm resistor, capacite wieh X= 18 ohms, and inductor

Allisa [31]

Answer:

the impedance of the circuit is 25.7 ohms.

Explanation:

It is given that,

Voltage, V = 50 volts

Frequency, f = 60 Hz

Resistance, R = 25 ohms

Capacitive resistance, $X_C=18\ ohms$

Inductive resistance, $X_L=24\ ohms$

We need to find the impedance of the circuit. It is given by :

$Z=\sqrt{R^2+(X_L-X_C)^2}$

$Z=\sqrt{25^2+(24-18)^2}$

Z = 25.7 ohms

So, the impedance of the circuit is 25.7 ohms. Hence, this is the required solution.

6 0

3 years ago