Answer:
C. both a speed and a direction
Answer:
a) X = 17.64 m
b) X = 17.64 + 4∆t^2 + 16.8∆t
c) Velocity = lim(∆t→0)〖∆X/∆t〗 = 16.8 m/s
Explanation:
a) The position at t = 2.10s is:
X = 4t^2
X = 4(2.10)^2
X = 17.64 m
b) The position at t = 2.10 + ∆t s will be:
X = 4(2.10 + ∆t)^2
X = 17.64 + 4∆t^2 + 16.8∆t m
c) ∆X is the difference between position at t = 2.10s and t = 2.10 + ∆t so,
∆X= 4∆t^2 + 16.8∆t
Divide by ∆t on both sides:
∆X/∆t = 4∆t + 16.8
Taking the limit as ∆t approaches to zero we get:
Velocity =lim(∆t→0)〖∆X/∆t〗 = 4(0) + 16.8
Velocity = 16.8 m/s
Gravity is the most likely force causing this phenomenon. please leave a thanks
acceleration of the car = 0.33 m/s²
Explanation:
To calculate the acceleration of the car we use the following formula:
acceleration = change in velocity / time
change in velocity = final velocity - initial velocity
change in velocity = 23 m/s - 13 m/s = 10 m/s
change in velocity = 10 m/s
acceleration = 10 m/s / 30 s
acceleration = 0.33 m/s²
Learn more about:
acceleration
brainly.com/question/4134594
brainly.com/question/1213762
#learnwithBrainly
