At a constant speed of 5.00 m/s, the speed at which the poodle completes a full revolution is

so that its period is
(where 1 revolution corresponds exactly to 360 degrees). We use this to determine how much of the circular path the poodle traverses in each given time interval with duration
. Denote by
the angle between the velocity vectors (same as the angle subtended by the arc the poodle traverses), then



We can then compute the magnitude of the velocity vector differences
for each time interval by using the law of cosines:


and in turn we find the magnitude of the average acceleration vectors to be

So that takes care of parts A, C, and E. Unfortunately, without knowing the poodle's starting position, it's impossible to tell precisely in what directions each average acceleration vector points.
One very handy electrical formula is
Power dissipated by a resistance = (Voltage)²/(resistance) .
24 kilowatts = (240 v)² / Resistance
Multiply each side by (Resistance):
(Resistance) x (24 kilowatts) = (240 v)²
Divide each side by (24 kilowatts):
Resistance = (240 v)² / (24,000 watts)
Resistance = (57,600 / 24,000) (volt² / volt · Amp)
Resistance = 2.4 (volt/Amp)
Resistance = 2.4 Ohms
Answer:
d = 9.69 cm
Explanation:
given,
mass of the block = 1.2 Kg
spring force constant(k) = 730 N/m
spring is compressed = d = ?
rough patch width = 5 cm
μ_k = 0.44
work done by friction = energy lost




d = 0.0969 m
d = 9.69 cm
Answer:
i wanna say 11 forgive me if wrong.
Explanation:
Answer:
Final velocity of the block = 2.40 m/s east.
Explanation:
Here momentum is conserved.
Initial momentum = Final momentum
Mass of bullet = 0.0140 kg
Consider east as positive.
Initial velocity of bullet = 205 m/s
Mass of Block = 1.8 kg
Initial velocity of block = 0 m/s
Initial momentum = 0.014 x 205 + 1.8 x 0 = 2.87 kg m/s
Final velocity of bullet = -103 m/s
We need to find final velocity of the block( u )
Final momentum = 0.014 x -103+ 1.8 x u = -1.442 + 1.8 u
We have
2.87 = -1.442 + 1.8 u
u = 2.40 m/s
Final velocity of the block = 2.40 m/s east.