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sergeinik [125]
3 years ago
11

Consider a string with a length of (47.5 A) cm tied at both end (like on a stringed instrument). If the frequency of the first h

armonic on the string is (245 B) Hz, determine the speed of the wave in the string. Post your answer in m/s and with 3 significant figures.
Physics
1 answer:
zubka84 [21]3 years ago
4 0

To solve this problem it is necessary to apply the concepts related to wavelength as a function of frequency and speed, as well as to determine the wavelength as a function of length.

From the harmonic vibration generated we know that the total length of the string will be equivalent to a half of the wavelength, that is

L = \frac{\lambda}{2} \rightarrow \lambda = 2L

Where,

\lambda = Wavelength

Therefore the wavelength for us would be,

\lambda = 2*47.5cm = 95cm = 0.95m

From the relationship of speed, frequency and wavelength we know that

\lambda = \frac{v}{f} \rightarrow v = \lambda f

v = (0.95m)(245Hz)

v = 232.75 m/s

Therefore the speed of the wave is 232.75m/s

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A spring on a horizontal surface can be stretched and held 0.5 m from its equilibrium position with a force of 60 N. a. How much
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Answer:

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Hooke's law states that the extension of a material is directly proportional to the applied force provided that the elastic limit is not exceeded. Mathematically;

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e is the extension of the material

From the formula, k = F/e

F1/e1 = F2/e2

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Work done = 1/2×120×5.5²

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Work done = 1815Joules

b) work done in compressing the spring 1.5m from its equilibrium position will be gotten using the same formula;

Work done = 1/2ke²

Work done =1/2× 120×1.5²

Works done = 60×1.5²

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