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3 years ago

What is the name of an element that have a atomic number of 82 and the atomic number of 207

Chemistry

1 answer:

balandron [24]3 years ago

5 0

This element is Lead (Pb).

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What is the unit of temperature on a solubility graph

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Answer:

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Explanation:

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2 years ago

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Explain the difference between the organism, population, and community levels of ecological organization

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Answer:

A population is a group of organisms belonging to the same species that live in the same area and interact with one another.

Explanation:

Levels of Ecological Organization

Level # 2. Population:

Level # 3. Community:

Level # 4. Ecosystem:

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2 years ago

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2 years ago

12579 nm rounded to 3 significant figures is

makkiz [27]

$\\ \sf\longmapsto 12579nm$

$\\ \sf\longmapsto 12579\times 10^{-9}m$

$\\ \sf\longmapsto 1257.9\times 10^{-8}m$

$\\ \sf\longmapsto 12.5\times 10^{-6}m$

$\\ \sf\longmapsto 12.5\mu m$

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2 years ago

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Write a net ionic equation for the reaction of hydrochloric acid with ammonia in aqueous solution. And write a net ionic equatio

zavuch27 [327]

Explanation:

(a) When aqueous solution of hydrochloric and ammonia chemically react together then it results in the formation of ammonium chloride.

The reaction equation for this reaction is as follows.

$HCl(aq) + NH_{3}(aq) \rightarrow NH_{4}Cl(aq)$

Now, ioni equation for this reaction is as follows.

$H^{+}(aq) + Cl^{-}(aq) + NH_{3}(aq) \rightarrow NH_{4}^{+}(aq) + Cl^{-}(aq)$

Cancelling the spectator ions, the net ionic reaction equation is as follows.

$H^{+}(aq) + NH_{3}(aq) \rightarrow NH^{+}_{4}(aq)$

(b) When sodium hydroxide chemically reacts with ammonium chloride then it forms ammonia, water and sodium chloride as follows.

$NaOH(aq) + NH_{4}Cl(aq) \rightarrow NH_{3}(aq) + NaCl(aq) + H_{2}O(l)$

Now, the total ionic equation will be as follows.

$Na^{+}(aq) + OH^{-}(aq) + NH^{+}_{4}(aq) + Cl^{-}(aq) \rightarrow NH_{3}(aq) + Na^{+}(aq) + Cl^{-}(aq) + H_{2}O(l)$

Cancelling the spectator ions from the above equation. Then the net ionic equation will be as follows.

$OH^{-}(aq) + NH^{+}_{4}(aq) \rightarrow NH_{3}(aq) + H_{2}O(l)$

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3 years ago

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