We are given with the mass percentage of the elements. Taking a 100-gram basis, we<span> convert the mass of the reactants to moles. Hydrogen is equal to 1.6 moles , nitrogen is equal to 1.3058 and oxygen is equal to 4.7625 moles. We divide each number </span>to <span>the least amount. Hence H is 1.22, N is 1.00 and O is 3.65. Answer is HNO3, nitric acid.</span>
The amount of N2O5 to start with would be 35.79 grams
<h3>Stoichiometric calculations</h3>
From the balanced equation of the reactions:
![2N_2O_5 --- > 4NO_2 + O_2](https://tex.z-dn.net/?f=2N_2O_5%20---%20%3E%204NO_2%20%2B%20O_2)
Mole ratio of N2O5 and NO2 = 1:2
Since the reaction's actual yield is 82%, the theoretical yield would be: 25 x 100/82 = 30.49 grams
Mole of 25 g NO2 = 30.49/46
= 0.66 mole
Equivalent mole of N2O5 = 0.54/2 mole
= 0.33 moles
Mass of 0.27 mole N2O5 = 0.33 x 108.01
= 35.79 grams
More on stoichiometric calculations can be found here: brainly.com/question/8062886
A variable is any factor,trait, or condition that can exist in differing amounts or types.
<h3>
Answer:</h3>
Gas law : Boyle's law
New pressure: 66.24 atm
<h3>
Explanation:</h3>
Concept tested: Gas laws (Boyle's law)
<u>We are given,</u>
- Initial pressure, P₁ = 2.86 atm
- Initial volume, V₁ = 8472 mL
- New volume, V₂ IS 365.8 mL
We need to determine the new pressure, P₂
- According to Boyle's law , the volume of a fixed mass of a gas and the pressure are inversely proportional at constant temperature.
- That is,
![P\alpha \frac{1}{V}](https://tex.z-dn.net/?f=P%5Calpha%20%5Cfrac%7B1%7D%7BV%7D)
- This means , PV = k (constant)
- Therefore; P₁V₁ = P₂V₂
- Rearranging the formula, we can get the new pressure, P₂
P₂ = P₁V₁ ÷ V₂
= (2.86 atm × 8472 mL) ÷ 365.8 mL
= 66.24 atm
Therefore, the new pressure is 66.24 atm
At the Freezing Point the particles in an object have no kinetic energy