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3 years ago

12

Please Help! Thank You

1 answer:

boyakko [2]3 years ago

3 0

Answer:

ooooooooooooooooh i dont know the answer

Explanation:

im not smart

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We want to find how much charge is on the electrons in a nickel coin. follow this method. a nickel coin has a mass of about 5 g.

Lady bird [3.3K]

The mass of a nickel coin is 5 g.
1 mol of Ni weighs 58 g. 1 mol contains 6.022 x 10²³ atoms of Ni.
therefore in 58 g there are 6.022 x 10²³ atoms of Ni
then in 5 g the number of Ni atoms are - 6.022 x 10²³ /58 x 5 = 5.2 x 10²² Ni atoms
Therefore number of Ni atoms are 5.2 x 10²² atoms in a nickel coin

3 0

3 years ago

Which line segment on the graph represents boiling

hoa [83]

1. There is no graph given

2. ENERGY LEVELS!!!

Boiling is the process of liquid(middle energy, flat line) turning into a gas(lots of energy, flat line), hope this helps

8 0

3 years ago

A compound is found to contain 50. 05% sulfur and 49. 95% oxygen by mass. What is the empirical formula for this compound? SO S2

jekas [21]

The empirical formula for the given compound has been $\rm SO_2$ . Thus, option C is correct.

The empirical formula has been the whole unit ratio of the elements in the formula unit.

<h3>Computation for the Empirical formula</h3>

The given mass of Sulfur has been, 50.05 g

The given mass of oxygen has been 49.95 g.

The moles of elements in the sample has been given by:

$\rm Moles=\dfrac{Mass}{Molar\;mass}$

Moles of Sulfur:

$\rm Moles\;S=\dfrac{50.05}{32}\\
 Moles\;S=1.56\;mol$

The moles of sulfur in the unit has been 1.56 mol.

Moles of Oxygen:

$\rm Moles\;O=\dfrac{49.95}{16} \\
Moles\;O=3.12\;mol$

The moles of oxygen in the unit has been 3.12 mol.

The empirical formula unit has been given as:

$\rm S_{1.56}O_{3.12}=SO_2$

Thus, the empirical formula for the given compound has been $\rm SO_2$ . Thus, option C is correct.

Learn more about empirical formula, here:

brainly.com/question/11588623

8 0

2 years ago

Which term describes a change that occurs with no new substances being formed?

Elina [12.6K]

C. physical change

Explanation:

That's the answer

8 0

3 years ago

How many kilograms of oseltamivir would be needed to treat all the people in a city with a population of 400000 people if each p

enyata [817]

Answer:

300 kg

Explanation:

The give parameters obtained from a similar question are;

The mass of oseltamivir per capsule = 75 mg

The mass of oseltamivir required, <em>M</em>, is given as follows;

M = The mass of oseltamivir per capsule × The mass taken per person per day × 5 days × The number of people in the city

M = 0.75 mg/capsule × 2 capsule/(day·person) × 5 days × 400,000 people

M = 300,000,000 mg = 300 kg

6 0

3 years ago