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Tcecarenko [31]
2 years ago
13

Problem 4: a long wire carries current towards east. a positive charge moves westward and just north from the wire. what is the

direction of the force experienced by this charge?
Physics
1 answer:
Alex787 [66]2 years ago
4 0
The direction of the force experienced by the positive charge is upward.

We can use the right-hand rule to understand the direction of the Lorentz force acting on the charge: let's put the thumb in the same direction of the current in the wire (eastward), while the other fingers "wrap themselves" around the wire. These other fingers give the direction of the Lorentz force in every point of the space around the wire. Since the charge is located north of the wire, in that point the fingers are directed upward, so the positive charge experiences a force directed upward.
(if it was a negative charge, we should have taken the opposite direction)
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A transformer consists of a 500 turn primary coil and a 2000-turnsecondary coil. If the current in the secondary is 3.0A, what i
Neporo4naja [7]

Answer:

The correct solution will be "12.0 A".

Explanation:

The given values are:

N_p= 500 \ turn

N_s= 200 \ turn

I_s= 3.0 \ A

By using the transformer formula, we get

⇒ \frac{N_p}{N_s}  =\frac{I_s}{I_p}

⇒ I_p = I_s\times \frac{N_s}{N_p}

On substituting the given values, we get

⇒      =3.0 \ A\times \frac{2000}{500}

⇒      =12.0 \ A

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3 years ago
Which of the following statements describe the transfer of energy a. Collision of atoms causing nuclear reactions B. A car speed
oksano4ka [1.4K]
I think the answer would be A.
8 0
2 years ago
The Cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of 100 m. Its name comes from its 60 arms, each of which can
Sonja [21]

Answer:

Explanation:

a ) speed of passenger = circumference / time

= 2π R / Time

= 2 x 3.14 x 50 / 60

= 5.23 m /s

b )

centrifugal force = m v² /R

= (882 /9.8 ) x 5.23² / 50

= 77.47 N

Apparent weight at the highest point

real weight  - centrifugal force

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= 804.53 N

Apparent weight at the lowest point

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= 882 +77.47

= 959.47 N

c )  if the passenger’s apparent weight at the highest point were zero

centrifugal force = weight

mv² /R = mg

v² = gR

= 9.8 X 50

v = 22.13 m /s

d )

apparent weight

mg - mv² / R

= 882 - (882 / 9.8 )x 22.13²/50

= 882 +  882

= 1764 N  

=

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2 years ago
Given three different locations on Earth's surface, where will the weight of a person be greatest?
Feliz [49]

Answer:

Explanation:

In order to answer this question, we simply have to refer to the laws of the equations of gravitational mechanics.

The equation given by Newton tells us that  

F = \frac{Gm_{1} m_{2}  }{r^{2} }

In the case where we compare a specific place where the Force of Gravity is greater or lesser, we focus on the term assigned to the Planet's Radius.

In the case of G, m_{1} ,m_{2}, we understand that they are constant.

We can easily notice that the more the Radius (Height seen from a viewer on the ground), the lower the force will be.

In other words, the smaller the radius in which the measurement is made with respect to the center of the earth, the greater the gravitational force.

In that order of ideas the smallest radio has South Pole, which is about 6356 km from the center of the Earth on the Equator line

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the rock of 10 kg is falling near the Earth's surface.assume that g =10N/kg and the is no air resistance. what is the accelerati
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Answer:

kya faltu sawal h repetitive g=10N/kg

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