- Standard reduction potential of Ag/Ag⁺ is 0.80 v and that of Cu⁺²(aq)/Cu⁰ is +0.34 V.
- The couple with a greater value of standard reduction potential will oxidize the reduced form of the other couple.
Ag⁺ will be reduced to Ag(s) and Cu⁰ will be oxidized to Cu²⁺
Anode reaction: Cu⁰(s) → Cu²⁺ + 2 e⁻ E⁰ = +0.34 V
Cathode reaction: Ag⁺(aq) + e → Ag(s) E⁰ = +0.80 V
Cell reaction: Cu⁰(s) + 2 Ag⁺(aq) → Cu⁺²(aq) + 2 Ag⁰(s)
E⁰ cell = E⁰ cathode + E⁰ anode
= 0.80 + (-0.34) = + 0.46 V
Stoichiometry is the field of chemistry that is concerned with the relative quantities of reactants and products in chemical reactions. For example, when oxygen and hydrogen react to produce water, one mole of oxygen reacts with two moles of hydrogen to produce two moles of water
Answer:
Explanation:
A) When four moles of ammonia reacts with five moles of O2 gas, four moles of Nitrogen mono oxide liberates along with six moles of water.
B) When two moles pottasium nitrate (KNO3) is heated it dissociates into two moles of potassium nitrite liberates along with one mole of O2 gas.
C) When one mole of calcium reacts with two moles water, one mole of calcium hydroxide obtained & one of hydrogen gas released.
D) When two mole of Sodium bicarbonate (NaHCO3) is heated it gradually decomposes to one mole of Sodium carbonate (Na2CO3) obtained along with one mole of each Water & Carbon dioxide.
E) <em>The question needs to corrected,</em>
When two moles of carbon monoxide reacts with one mole oxygen two moles of carbon dioxide is released.
Answer:
they are used to record the motion of the ground
Explanation:
When we balance the given equation
SF₆(g) + SO₃(g) → SO₂F₂(g)
We will get
SF₆(g) + 2SO₃(g) → 3SO₂F₂(g)
Solution:
Balancing the given equaation
SF₆(g) + SO₃(g) → SO₂F₂(g)
We have to balance the given number of O
SF₆(g) + 2SO₃(g) → 3SO₂F₂(g)
We get balanced equation
SF₆(g) + 2SO₃(g) → 3SO₂F₂(g)
The reaction quotient will be
Qc = [product] / [reactant]
Qc = [SO₂F₂(g)] / [SF₆(g) + SO₃(g)]
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