Plz help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

The equilibrium constant, Kp, for the following reaction is 9.52Ã10-2 at 350 K: CH4(g) + CCl4(g) 2CH2Cl2(g). Calculate the equil

Nimfa-mama [501]

Answer:

A) p CH₄ = 0.732 atm

B) p CCl₄ = 0.732 atm

c) p CH₂Cl₂ = 0.22 atm

Explanation:

we have the equilibrium constant for this problem, along the initial pressures for the reactants, and need to find the partial pressures at equilibrium. So lets setup the equilibrium:

CH₄ (g) + CCl₄ (g) ⇔ 2 CH₂Cl₂ (g) Kp = 9.50 x 10⁻²

where Kp is given by :

Kp = p CH₂Cl₂ ² / p CH₄ x p CCl₄

where p are the partial pressures

p CH₄ atm p CCl₄ atm p CH₂Cl₂ atm

initial 0.844 0.844 0

change - x - x +2x

equilibrium 0.844 - x 0.844 - x 2 x

Kp = 9.52 x 10⁻² = ( 2x )²/ (( 0.844 - x ) x ( 0.844 - x ))

9.52 x 10⁻² = (2x)² / ( 0.844 - x )²

Taking square root to both sides of the equation:

√9.52 x 10⁻² = 2x / (0.844 - x )

0.309 = 2x / (0.844 - x)

0.260 - 0.309 x = 2x

0.260 = 2.309 x ⇒ x = 0.112

So the partial pressures are at equilibrium are:

p CH₄ = p CCl₄ = 0.844 - 0.112 = 0.732 atm

p CH₂Cl₂ = 2 x (0.112 atm) = 0.224 atm

You can check your answer is correct by plugging this values and comparing with the given Kp.

6 0

3 years ago

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Caproic acid, responsible for the odor of dirty socks, is composed of C, H, and O atoms. Combustion of a 0.225-g sample of this

puteri [66]

Answer: Empirical formula = C3H6O

C6H1202---Molecular formula

Explanation:

we first find the masses of C, H and O contained in the sample

mass of carbon

Mass of CO2 = 0.512g

molar mass of carbon = 12g/mol

Molar mass CO2 = 12+ (16X2)=44g/mol

Mass C = 12/44x 0.512 = 0.1396g of carbon

Mass Hydrogen

mass of H2O= 0.209g

Molar mass H2O = 18g/mol

Molar mass Hydrogen = 1.0079g x 2 = 2.0158g since Hydrogen gas is diatomic

Mass H = 2.0158/18 X 0.209 = 0.0234g Hydrogen

Mass of Oxygen in the sample = overall mass of Sample - mass of hydrogen and oxgen=

0.225 - ( 0.1396 + 0.0234) = 0.062g Oxygen

A) T o find Empirical formula

1ST STEP-- Divide through by each relative atomic mass:

C = 0.1396/12 = 0.01163

H = 0.0234/1.0079 = 0.0232

O = 0.0619/16 = 0.00387

2nd step Divide by smallest answer

C = 0.01163/0.00387 = 2.0998 = 3

H = 0.0232/0.00387 = 5.99 = 6

O = 0.00387/0.00387=1

Empirical formula = C3H6O

B)To find molecular formula

Given that molar mass of caproic acid as 116g,

we will use our empirical formulae to find molecular formulae with the equation

(C3H6O)n= 116g/mol

12x3 + 1x6 + 1 x16= 58g/mol

58n= 116g/mol

n = 116/58= 2

= (C3H6O)2= C(3X2) H(6X2) O(1X2)

C6H1202--- MOLECULAR FORMULA

7 0

3 years ago

the internal energy of an ideal gas depends only on its temperature. Do a first-law analysis of this process. A sample of an ide

Aleks04 [339]

Answer:

Check Explanation

Explanation:

The Mathematical expression of the first law is given as

ΔU = Q - W

Note that depending on convention, the mathematical expression for the first law can be written as

ΔU = Q + W

a) Yes, the gas does work on its surroundings. Since it expands; indicating that there is a change in volume.

The work done is given as -PΔV if we are using the convention of (ΔU = Q + W). And this work is negative work done, since the system expands and does work on the surroundings.

But if we are using the convention of (ΔU = Q - W), the work done is given as PΔV and the workdone by the system on the environment is positive work during expansion.

b) Since this all takes place at constant temperature and against a constant atmospheric pressure, the change in internal energy for this system is 0. Change in internal energy depends on a change in temperature.

So, from the mathematical expression,

ΔU = Q + W or ΔU = Q - W

If ΔU = 0,

Q = - W or Q = W

But either ways,

Q = PΔV

(because, W = -PΔV for ΔU=Q+W and W = PΔV for ΔU=Q-W)

So, either ways, the heat transfer is the same and it is positive. This indicates heat is transferred from the surroundings to the system.

(c) What is ΔU for the gas for this process?

Since this all takes place at constant temperature and against a constant atmospheric pressure, the change in internal energy for this system is 0. Change in internal energy depends on a change in temperature.

Hope this Helps!!!

8 0

4 years ago

Calcular la cantidad de NaOH necesaria para preparar medio litro de disolución 2,5 N. (Dato: peso molecular del NaOH = 40 g/mol)

kolbaska11 [484]

Answer:

The amount of NaOH required to prepare a solution of 2.5N NaOH.

The molecular mass of NaOH is 40.0g/mol.

Explanation:

Since,

NaOH has only one replaceable -OH group.

So, its acidity is one.

Hence,

The molecular mass of NaOH =its equivalent mass

Normality formula can be written as: $Normality=\frac{mass of solute NaOH}{its equivalent mass} * \frac{1}{volume of solution in L} \\$

Substitute the given values in this formula to get the mass of NaOH required.

$2.5N=\frac{mass of NaOH}{40g/mol} *\frac{1}{1L} \\mass of NaOH=2.5N*40gmol\\ = 100.0g$

Hence, the mass of NaOH required to prepare 2.5N and 1L. solution is 100g

8 0

3 years ago

After Frank Palko was sentenced to death by the state of Connecticut, the Supreme Court ruled that

GREYUIT [131]

The answer is "his conviction and execution should be upheld". Frank Palko was first charged with murder and claimed that Connecticut violated the Double Jeopardy Clause of the Fifth Amendment. The fifth amendment states that "there must be no person to be put twice in jeopardy of life and limb" so this was the violation the court made after they charge him with murder for the second time. That's why when the second trial was made,he was sentenced to by the Supreme court which decided that he should be executed and convicted because of the evidences found.

4 0

3 years ago

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