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atroni [7]
3 years ago
5

When the oxide of generic metal M is heated at 25C, only a negligible amount of M is produced. MO2(s) <---> M(s)+O2(g) del

ta G = 288.5 kJ/mol
1.) When the reaction is coupled to the conversion of graphite to carbon dioxide, it becomes spontaneous. What is the chemical equation of this coupled process? Show that the reaction is in equilibrium, include physical states, and represent graphite as C(S) _________________________________
2.) What is the thermodynamic equilibrium constant for the coupled reaction? K = ????
Chemistry
1 answer:
Valentin [98]3 years ago
3 0

Answer:

1. MO_2(s)+C(s)CO_2(g)+M(s)

2. K=3.57x10^{18}

Explanation:

Hello,

1.) By coupling the given reaction with the formation of carbon dioxide, one states the total reaction as:

MO_2(s)M(s)+O_2(g)\\C(s)+O_2(g)CO_2(g)

____________________________________

MO_2(s)+C(s)CO_2(g)+M(s)

2.) Now, since we know that the Gibbs free energy for the decomposition of the metal is 288.5kJ/mol and the Gibbs free energy for the formation of carbon dioxide has a value of −394.39kJ/mol, the total Gibbs free energy for this process is:

ΔG^o=288.5kJ/mol-394.39kJ/mol=-105.89kJ/mol

So the equilibrium constant is:

K=exp(-\frac{DeltaG^0}{RT} )\\K=exp(-\frac{-105890J/mol}{8.314J/molK*298.15K} )\\K=3.57x10^{18}

Best regards.

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Determine how many ml of water you need to remove, by evaporation, if you have a 500 ml of 10.20 M HNO3 dilute solution and you
Ludmilka [50]

The total volume of water that would be removed will be 75 mL

<h3>Dilution equation</h3>

Using the dilution equation:

M1V1 = M2V2

In this case, M1 = 500 mL, V1 = 10.20 M, M2 = 12 M

Substitute:

V2 = 500 x 10.20/12

         = 425 mL

The final volume in order to arrive at 12 M HNO3 would be 425 mL from the initial 500 mL. Thus, the total amount of water that will be removed by evaporation can be calculated as:

500 - 425 = 75 mL

More on dilution can be found here: brainly.com/question/7208939

7 0
2 years ago
Science is based primarily on peoples opinions and views of the subject matter.
kvv77 [185]

Answer:

False

Explanation:

Science is not based on primarily on peoples opinions and views of the subject matter whereas science is based on empirical observations and research for its validity.

<u>Science aims to find answers to human questions related to the natural world through their research observation and experiments. Scientists and researchers provide valid proof of human questions so that people can trust them.</u>

Science can change people's opinions regarding the natural world with valid proof and observational theories but science is not based on people's opinion.

Hence, the given statement is "false".

7 0
3 years ago
You mix 200. mL of 0.400M HCl with 200. mL of 0.400M NaOH in a coffee cup calorimeter. The temperature of the solution goes from
GuDViN [60]

Answer : The enthalpy of neutralization is, 56.012 kJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol

\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol

The balanced chemical reaction will be,

HCl+NaOH\rightarrow NaCl+H_2O

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.08 mole of HCl neutralizes by 0.08 mole of NaOH

Thus, the number of neutralized moles = 0.08 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = 200mL+200L=400mL

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 400mL=400g

Now we have to calculate the heat absorbed during the reaction.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = ?

c = specific heat of water = 4.18J/g^oC

m = mass of water = 400 g

T_{final} = final temperature of water = 27.78^oC=273+25.10=300.78K

T_{initial} = initial temperature of metal = 25.10^oC=273+27.78=298.1K

Now put all the given values in the above formula, we get:

q=400g\times 4.18J/g^oC\times (300.78-298.1)K

q=4480.96J

Thus, the heat released during the neutralization = -4480.96 J

Now we have to calculate the enthalpy of neutralization.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of neutralization = ?

q = heat released = -4480.96 J

n = number of moles used in neutralization = 0.08 mole

\Delta H=\frac{-4480.96J}{0.08mole}=-56012J/mole=-56.012kJ/mol

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 56.012 kJ/mole

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Answer:

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Which of the following is the chemical formula for Hydrogen Chloride?
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