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ivanzaharov [21]
3 years ago
13

Would the concentration of hydroxide ion in a 0.30 m solution of potassium hydroxide (koh) be greater than, less than, or equal

to 0.30 m?
Chemistry
1 answer:
patriot [66]3 years ago
6 0

Potassium hydroxide KOH is a strong base which can completely ionize to form potassium and hydroxide ions.

The equation representing ionization of KOH,

KOH(aq)-->K^{+}(aq)+OH^{-}(aq)

The mole ratio of hydroxide to KOH from the above equation is \frac{1molOH^{-} }{1molKOH}

The given concentration of KOH solution=0.30M

Calculating the concentration of hydroxide ions present in 0.30M KOH solution:

\frac{0.30mol KOH}{L} *\frac{1mol OH^{-} }{1 mol KOH} =0.30\frac{mol}{L}OH^{-}

Therefore the concentration of hydroxide ion will be equal to 0.30 M in a 0.30 M KOH solution.

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What is the concentration of H3O+ ions in saliva if [OH-] = 4.22 x 10-10 M? Provide the pH and the classification of this sample
OLEGan [10]

pH=4.625

The classification of this sample of saliva : acid

<h3>Further explanation</h3>

The water equilibrium constant (Kw) is the product of concentration

the ions:

Kw = [H₃O⁺] [OH⁻]

Kw value at 25° C = 10⁻¹⁴

It is known [OH-] =  4.22 x 10⁻¹⁰ M

then the concentration of H₃O⁺:

\tt 10^{-14}=4.22\times 10^{-10}\times [H_3O^+]\\\\(H_3O^+]=\dfrac{10^{-14}}{4.22\times 10^{-10}}=2.37\times 10^{-5}

pH=-log[H₃O⁺]\tt pH=5-log~2.37=4.625

Saliva⇒acid(pH<7)

6 0
3 years ago
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Alekssandra [29.7K]

Answer:

Its B :)

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7 0
3 years ago
Draw a bond-line structure for CH3CH2O(CH2)2CH(CH3)2.<br><br> Include Lone Pairs in your answer.
mash [69]

Answer:

See explanation and image attached

Explanation:

A bond line structure refers to any structure of a covalent molecule wherein the covalent bonds present in the molecule are represented with a single line for each level of bond order.

The bond-line structure of CH3CH2O(CH2)2CH(CH3)2 has been shown in the image attached. We know that oxygen has a lone pair of electrons and this has been clearly shown also in the image attached.

7 0
3 years ago
What mass of sodium hydroxide is needed to neutralise 24.5kg of sulfuric acid <br> H2SO4 + N2 = 2NH3
sveticcg [70]

Answer:

23.92 g

Explanation:

Molar mass of H2SO4 = (2×1)+32+(16×4)= 2+32+48= 82g/mol

H2SO4 + 2NaOH ---> Na2SO4 + 2H2O

I mole of H2SO4 = 2 moles of NaOH

24.5/82 = 24.5/82 × 2

= 0.598 moles of NaOH will neutralize

Mass= mole× molar mass

Molar mass of NaOH= 23+16+1 = 40g/mol

Mass= 0.598 × 40 = 23.92g of NaOH

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3 years ago
What is the pH of a 4.7 x 10-9 M HCl solution? *
ValentinkaMS [17]
11.21 or 2.93 I think
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3 years ago
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