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lora16 [44]
4 years ago
8

On a coordinate plane, a curved line with minimum values of (negative 2, 0) and (2.4, negative 51) and a maximum value of (negat

ive 0.75, 6), crosses the x-axis at (negative 2, 0), (0, 0), and (3.5, 0), and crosses the y-axis at (0, 0). Which statement is true about the end behavior of the graphed function?
Mathematics
2 answers:
Dvinal [7]4 years ago
7 0

Answer:

b

Step-by-step explanation:

Lilit [14]4 years ago
3 0

Answer:

B

Step-by-step explanation:

You might be interested in
Write - 24/4 in simplest form
mina [271]

Answer:

-6 ,

Step-by-step explanation:

24 divided by 4 = 6

5 0
3 years ago
Read 2 more answers
Find the domain of each function. (Enter your answers using interval notation.)(a) f(x)=8/(1+e^x) .(b) f(x)=5/(1−e^x)
Alexus [3.1K]

Answer:

domain is  (-∞,∞)

(-∞,0) U(0,∞)

Step-by-step explanation:

f(x)=\frac{1}{1+e^x}

The domain is the set of x values for which the function is defined

In f(x) there is no restriction for x. the function is defined for all x values

so domain is  (-∞,∞)

f(x)=\frac{5}{1-e^x}

The domain is the set of x values for which the function is defined

when x=0, e^0=1 that makes the denominator 0

Denominator 0 is undefined. So x cannot be 0

domain is (-∞,0) U(0,∞)

3 0
4 years ago
Alex wrote 103.903 in expanded form as 100+3x1+9x1/100+3x1/1000. Explain his mistake. Then tell how to correct it.
masya89 [10]
Here is the mistake is on 9x1/100 because after decimal 9 is there means
9 has to be multiplied by 1/10 to get the 0.9

Here if we expand the 103.903 then from left to right
1 = 1x100 +
0 = 0x10   +
3 = 3x1     +
9 = 9x1/10+
0 = 0x1/100+
3 = 3x1/1000 = 103.903
7 0
3 years ago
Is this correct?? :)
dimaraw [331]
No it not correct because you had forgot to  divide +5 form -2 and that will give you it will be 2.5 but in fraction form it will be -2 1/2
6 0
3 years ago
Question is in picture
Marta_Voda [28]

|2x|\geq1\\\\2x\ge1 \ \ \text{or} \ \ 2x\leq-1\\\\\huge\boxed{x\geq\frac{1}{2} \ \ \text{or} \ \ x\leq-\frac{1}{2}}

7 0
3 years ago
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