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padilas [110]
3 years ago
10

Calculate the total volume of gas produced at 22 c and 1.02 atm by the complete decomposition of 11.83 g of potassium chlorate

Chemistry
1 answer:
Elis [28]3 years ago
6 0
Use Ideal gas law to solve. PV=mRT you have pressure (1.02atm), temperature (295K or 22°C), mass of KClO3(11.83g) , and universal gas constant on a molar mass basis (R=R_bar/M). Just make sure you units are consistent and use the ideal gas equation to solve for Volume. M, should be the total Molar mass for KClO3.
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Based on the information in the graph, what is the relationship between air temperature and the amount of water vapor that the a
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Explanation:

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If the density of water is 1g/cm3 what is its specific gravity
MakcuM [25]

Answer:

Specific gravity is the density of asubstance divided by the density of water. Since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density(but without any units).

8 0
3 years ago
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Be sure to answer all parts. Consider the formation of ammonia in two experiments. (a) To a 1.00−L container at 727°C, 1.30 mol
Sonbull [250]

<u>Answer:</u> The value of K_c for 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g) reaction is 5.13\times 10^2

<u>Explanation:</u>

We are given:

Initial moles of nitrogen gas = 1.30 moles

Initial moles of hydrogen gas = 1.65 moles

Equilibrium moles of ammonia = 0.100 moles

Volume of the container = 1.00 L

For the given chemical equation:

                N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

<u>Initial:</u>            1.30       1.65

<u>At eqllm:</u>       1.30-x    1.65-3x             2x

Evaluating the value of 'x'

\Rightarrow 2x=0.100\\\\\Rightarrow x=0.050mol

The expression of K_c for above equation follows:

K_c=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}

Equilibrium moles of nitrogen gas = (1.30-x)=(1.30-0.05)=1.25mol

Equilibrium moles of hydrogen gas = (1.65-x)=(1.65-0.05)=1.60mol

Putting values in above expression, we get:

K_c=\frac{(0.100)^2}{1.25\times (1.60)^3}\\\\K_c=1.95\times 10^{-3}

Calculating the K_c' for the given chemical equation:

2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)

K_c'=\frac{1}{K_c}\\\\K_c'=\frac{1}{1.95\times 10^{-3}}=5.13\times 10^2

Hence, the value of K_c for 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g) reaction is 5.13\times 10^2

8 0
3 years ago
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From a laboratory process designed to separate water into hydrogen and oxygen gas, a student collected 20.0g of Hydrogen and 158
denis23 [38]

Answer:

it is water 2

Explanation:

3 0
1 year ago
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