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padilas [110]
3 years ago
10

Calculate the total volume of gas produced at 22 c and 1.02 atm by the complete decomposition of 11.83 g of potassium chlorate

Chemistry
1 answer:
Elis [28]3 years ago
6 0
Use Ideal gas law to solve. PV=mRT you have pressure (1.02atm), temperature (295K or 22°C), mass of KClO3(11.83g) , and universal gas constant on a molar mass basis (R=R_bar/M). Just make sure you units are consistent and use the ideal gas equation to solve for Volume. M, should be the total Molar mass for KClO3.
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Explanation:

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3 years ago
5. Write the chemical formulae of the following chemical compounds.
Vladimir [108]

Answer:

  1. Na2SO4
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3 years ago
blast furnaces give off many unpleasant and unhealthy gases. If the total air pressure is .99 ATM the partial pressure of carbon
kolbaska11 [484]

Answer:

P_{air}=1.02atm

Explanation:

Hello!

In this case, since the Dalton's law help us to realize that the total pressure of a gas mixture is computed by adding the partial pressure of each composing gas, for the mixture formed by carbon dioxide, oxygen sulfide (should be hydrogen sulfide instead) and air, we can write:

P=P_{CO_2}+P_{H_2S}+P_{air}

Thus, given the total pressure and the partial pressures of both carbon dioxide and hydrogen sulfide, the partial pressure of the remaining air would be:

P_{air}=P_{T}-P_{H_2S}-P_{CO_2}

Therefore, we plug in to obtain:

P_{air}=0.99atm-0.05atm-0.02atm\\\\P_{air}=1.02atm

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3 years ago
After the completion of a gas forming reaction, the column of water remaining in the collection flask was measured to me 55 mm h
baherus [9]

Answer:

The partial pressure of the gas produced by the reaction is 0.9187 atm

Explanation:

Given;

vapor pressure of water, \rho_w = 0.0313 atm

measured atmospheric pressure, P_{Total} = 0.950 atm

partial pressure of the gas produced by the reaction = ?

According to Dalton's law of partial pressure; total pressure is equal to sum of partial pressure of water vapor and gas produced.

P_{Total} = P_{gas} + P_{water}

P_{gas} = P_{Total} -P_{water}

P_{gas} = 0.95 - 0.0313

P_{gas} = 0.9187 atm

Therefore, the partial pressure of the gas produced by the reaction is 0.9187 atm

3 0
4 years ago
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