Answer:
None
Step-by-step explanation:
A high pH is caused by an excess of hydrogen ions over hydroxide ions.
Hydrogen ions are so small that they pass through the pores of an ordinary filter.
Thus, ordinary filtration has no effect on the pH of water.
I think the correct answer from the choices listed above is the last option. The formula for phosphorous acid is H3PO3. It <span>also called orthophosphorous acid, one of several oxygen acids of phosphorus, used as reducing agent in chemical analysis. Hope this answers the question.</span>
The spectator ions in the reaction between aqueous 
and aqueous HCl would be 
and 
ions.
<h3>What are spectator ions?</h3>
Spectator ions are anions or cations that exist both as reactants and as products in a reaction. Their forms remain unchanged both in the reactants and in the products.
Aqueous and aqueous HCl react according to the following equation:
Before the reaction, and existed in the reactants as and HCl respectively. After the reaction, and exist as 
in the product.
Thus, the spectator ions in this case are and ions because their forms did not change after the reaction.
More on spectator ions can be found here: brainly.com/question/28913274
#SPJ1
B. Electrons because
A - Protons always remain constant. They decay over a LONG period of time and don't do anything.
B - it is correct because they do all the bonding.
C - It's not a subatomic particle
D - Neutrons are not involved in bonding as well.
Answer:
1.2 M
1.2 m
Explanation:
There is some info missing. I think this is the original question.
<em>A student dissolves 5.1g of ammonia (NH₃) in 250 mL of a solvent with a density of 1.02 g/mL. The student notices that the volume of the solvent does not change when the ammonia dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits.</em>
<em />
Molarity
The molar mass of ammonia is 17.03 g/mol. The moles corresponding to 5.1 grams is:
5.1 g × (1 mol/17.03 g) = 0.30 mol
The volume of the solution is equal to the volume of the solvent, 250 mL or 0,250 L.
The molarity of ammonia is:
M = moles of solute / liters of solution
M = 0.30 mol / 0.250 L
M = 1.2 M
Molality
The density of the solvent is 1.02 g/mL. The mass corresponding to 250 mL is:
250 mL × 1.02 g/mL = 255 g = 0.255 kg
The molality of ammonia is:
m = moles of solute / kilograms of solvent
m = 0.30 mol / 0.255 kg
m = 1.17 m ≈ 1.2 m
