Answer:
10.76 grams
Explanation:
Given that the amount of
is 25.0 grams.
Mass of 1 mole of
= 158 grams
The number of atoms in 1 mole of
is 4.
Mass of oxygen in 1 mole of
= 16\times 4 = 68 grams.
Here, 158 grams of
has 68 grams of oxygen
So, the amount of oxygen in 1 gram of
= 68/158 grams
Therefore, the amount of oxygen in 1 gram of
=
grams
=10.76 grams
Hence, 25 grams of
has 10.76 grams of oxygen.
<span>6 + x = 12. To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12. If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.</span>
I: Current
V: Voltage
R: resistance
you’re welcome ;)
Answer:
Explanation:
At three-quarters of a teaspoon of baking soda, the cookie's texture becomes fragile like that of a soda cracker, with a deeply roasted flavor that distracts from the ginger.
Answer:
Explanation:
Initial burette reading = 1.81 mL
final burette reading = 39.7 mL
volume of NaOH used = 39.7 - 1.81 = 37.89 mL .
37.89 mL of .1029 M NaOH is used to neutralise triprotic acid
No of moles contained by 37.89 mL of .1029 M NaOH
= .03789 x .1029 moles
= 3.89 x 10⁻³ moles
Since acid is triprotic , its equivalent weight = molecular weight / 3
No of moles of triprotic acid = 3.89 x 10⁻³ / 3
= 1.30 x 10⁻³ moles .