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svetoff [14.1K]
3 years ago
11

5. The Santa Ana winds, also known as "devil winds", are strong and dry high-pressure masses of air that begin in the Great Basi

n mountains and then affect coastal areas in Southern California. Assume that these winds consists of a mixture of nitrogen and oxygen gases that behave ideally and that they begin at a pressure and temperature of 0.705 atm of 22.0 0C, respectively, and that this mass of air is then adiabatically and reversibly compressed to a pressure of 1.00 atm when it descends to the coastal regions. Calculate the final temperature.
Chemistry
1 answer:
meriva3 years ago
7 0

Answer:

Explanation:

Given that;

The initial pressure = 0.705 atm

The initial temperature = 22.0° C

The final pressure = 1.00 atm

The objective is to calculate the final temperature,

Since the change occurs adiabatically and reversibly, the final temperature can be calculated by using the thermodynamics equation:

(\dfrac{T_2}{T_1})^r= (\dfrac{P_2}{P_1})^{r-1}

where;

r = 7/5 = 1.4

(\dfrac{T_2}{22.0^0})^{1.4}= (\dfrac{1.00}{0.705})^{1.4-1}

(\dfrac{T_2}{22.0^0})^{1.4}= (1.418)^{0.4}

T_2 = 22 \times 1.418 ^{^{\frac{0.4}{1.4}}

T_2 = 22 \times 1.418 ^{{0.286}

T_2 =24.31^0 \ C

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Answer:

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Explanation:

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Expression of rate law of the reaction will be written as:

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Rate(R) of the reaction in trail 1 ,when :

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9.0\times 10^{-5} M/s=k[0.30 M]^a[0.30 M]^b[0.30 M]^c...[1]

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Rate(R) of the reaction in trail 3 ,when :

[A]=0.60 M,[B]=0.30 M,[C]=0.30 M

R=3.6\times 10^{-4} M/s

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Rate(R) of the reaction in trail 4 ,when :

[A]=0.60 M,[B]=0.60 M,[C]=0.30 M

R=3.6\times 10^{-4} M/s

3.6\times 10^{-4} M/s=k[0.60 M]^a[0.60 M]^b[0.30 M]^c...[4]

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c = 1

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b = 0

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Rate law of reaction is :

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Rate constant of the reaction = k

9.0\times 10^{-5} M/s=k[0.30 M]^2[0.30 M]^0[0.30 M]^1

k=\frac{9.0\times 10^{-5} M/s}{[0.30 M]^2[0.30 M]^0[0.30 M]^1}

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RideAnS [48]

Answer:

See explanation

Explanation:

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Answer:

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