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svetoff [14.1K]
3 years ago
11

5. The Santa Ana winds, also known as "devil winds", are strong and dry high-pressure masses of air that begin in the Great Basi

n mountains and then affect coastal areas in Southern California. Assume that these winds consists of a mixture of nitrogen and oxygen gases that behave ideally and that they begin at a pressure and temperature of 0.705 atm of 22.0 0C, respectively, and that this mass of air is then adiabatically and reversibly compressed to a pressure of 1.00 atm when it descends to the coastal regions. Calculate the final temperature.
Chemistry
1 answer:
meriva3 years ago
7 0

Answer:

Explanation:

Given that;

The initial pressure = 0.705 atm

The initial temperature = 22.0° C

The final pressure = 1.00 atm

The objective is to calculate the final temperature,

Since the change occurs adiabatically and reversibly, the final temperature can be calculated by using the thermodynamics equation:

(\dfrac{T_2}{T_1})^r= (\dfrac{P_2}{P_1})^{r-1}

where;

r = 7/5 = 1.4

(\dfrac{T_2}{22.0^0})^{1.4}= (\dfrac{1.00}{0.705})^{1.4-1}

(\dfrac{T_2}{22.0^0})^{1.4}= (1.418)^{0.4}

T_2 = 22 \times 1.418 ^{^{\frac{0.4}{1.4}}

T_2 = 22 \times 1.418 ^{{0.286}

T_2 =24.31^0 \ C

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A sample of gas has a volume of 100. L at 17 °C and 800. torr. To what temperature must the gas be cooled in order for its volum
Romashka [77]

Answer:

108.81 K

Explanation:

First convert 17 °C to Kelvin:

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Assuming ideal behaviour, we can solve this problem by using the<em> combined gas law</em>, which states that at constant composition:

  • P₁V₁T₂=P₂V₂T₁

Where in this case:

  • P₁ = 800 torr
  • V₁ = 100 L
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  • P₂ = 600 torr
  • V₂ = 50 L
  • T₁ = 290.16 K

We <u>input the data</u>:

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And <u>solve for T₂</u>:

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6 0
3 years ago
Complete the equation determine if there are precipitates write the balanced ionic and net ionic equations. If there is no preci
alukav5142 [94]

You may find bellow the balanced chemical equations.

Explanation:

Molecular equations:

3 Sr(NO₃)₂ (aq) + 2 K₃PO₄ (aq) → Sr₃(PO₄)₂ (s) + 6 KNO₃ (aq)

2 NaOH (aq) + Ni(NO₃)₂ (aq) = Ni(OH)₂ (s) + 2 NaNO₃ (aq)

Ionic equations:

3 Sr²⁺ (aq) + 6 NO₃⁻ (aq) + 6 K⁺ (aq) + 2 PO₄³⁻ (aq) →  Sr₃(PO₄)₂ (s) + 6 K⁺ (aq) + 6 NO₃⁻ (aq)

2 Na⁺ (aq) + 2 OH⁻ (aq) + Ni²⁺ (aq) + 2 NO₃⁻ (aq) = Ni(OH)₂ (s) + 2 Na⁺ (aq) + 2 NO₃⁻ (aq)

To get the net ionic equation we remove the spectator ions:

3 Sr²⁺ (aq) + 2 PO₄³⁻ (aq) →  Sr₃(PO₄)₂ (s)

2 OH⁻ (aq) + Ni²⁺ (aq) = Ni(OH)₂ (s)

Learn more about:

net ionic equations

brainly.com/question/7018960

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4 0
3 years ago
Would you expect the carbonyl carbon of benzaldehyde to be more or less electrophilic than that of acetaldehyde? Explain using r
Slav-nsk [51]

Answer:

Benzaldehyde is less electrophilic than acetaldehyde

Explanation:

Electrophilicity of carbonyl carbon depends on it's positive charge density.

In benzaldehyde, phenyl group can act as an electron donating group towards carbonyl group due to it's electron donating resonating effect.

In acetaldehyde, methyl group can act as an electron donating group towards carbonyl group due to it's electron donating inductive effect.

We know that resonating effect are more stronger than inductive effect.

Henece, it is expected that positive charge density on carbonyl carbon is much lower in benzaldehyde than acetaldehyde.

So, benzaldehyde is less electrophilic than acetaldehyde.

Resonating effect of phenyl group has been shown below.

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A sample of a solid labeled as NaCl may be impure. a student analyzes the sample and determines that it contains 75 percent chlo
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Answer:

D

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(BRAINLIEST QUEATION)
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1. Methyl orange indicator: This shows pH in a colouess solution if it changes from colourless to red.

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8 0
3 years ago
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