The coefficient of friction must be 0.196
Explanation:
For a car moving on a circular track, the frictional force provides the centripetal force needed to keep the car in circular motion. Therefore, we can write:
where the term on the left is the frictional force acting between the tires of the car and the road, while the term on the right is the centripetal force. The various terms are:
is the coefficient of friction between the tires and the road
m is the mass of the car
is the acceleration of gravity
v is the speed of the car
r is the radius of the curve
In this problem,
r = 750 m is the radius
is the speed
And solving for
, we find the coefficient of friction required to keep the car in circular motion:

Learn more about circular motion:
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We will define the Total mass to calculate the force, so our values are:
Total Mass 
The Weight is,

Through the hook's Law we calculate X.
, where x is the lenght of compression and K the Spring constant.
We don't have a K-Spring, but we can assume a random value (or simply let the equation in function of K)

I assume a value of 

Answer:
k is the energy of motion it increase with four of load you carry
Hello!
To answer your question, salt is a compound!
It is the product of the chemical bond between Na (Sodium) and Cl (Chloride),
Hopes this help you with your question.
<span>According to newton's second law of motion,the acceleration of an object equals the net force acting on the object divided by the objects "Mass"
Hope this helps!</span>