Given:
u = 273 m/s, horizontal launch speed
h = 3.27 km = 3270 m, altitude.
v = 0, vertical launch speed
g = 9.8 m/s².
Wind resistance is ignored.
The time, t, for the bomb to reach the ground is given by
0t + (1/2)gt² = h
4.9t² = 3270
t² = 667.3469
t = 25.833 s
The horizontal distance traveled is
273*25.833 = 7052.4 m = 7.0524 km
Answer: 7.05 km
Answer:
Statement A=3.5504m²
Statement B=3.57576m²
Explanation:
The area of a rectangle is gotten by multiplying the length of the rectangle by the width of the rectangle which gives us the surface area which the rectangle covers. For statement A, I multiplied 2.536 by 1.4 and for statement B, I multiplied 2.536 by 1.41
If you could hear it at all, it would sound very soft.
Q = I t = 30 x 120 = 3600 C
