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Inessa [10]
4 years ago
9

Beginning about 55 seconds into the video, you'll see an animation of a photographer looking through her camera at a man, a set

of trees, and distant mountains. Notice that, as viewed through the camera, the positions of the man and the trees change (relative to distant mountains) as the photographer moves. Which of the following statements correctly describes what is really happening in this situation?
Physics
1 answer:
RideAnS [48]4 years ago
5 0

Answer and Explanation

The concept of parallax and relative motion is responsible for this.

That is, the photographer's motion prompts her to see parallax for the man and the trees, because their positions appear to keep shifting even though they are not really moving.

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Pea plant clones are given different amounts of water for a three-week period. The first pea plant receives 400 milliliters a da
musickatia [10]

Answer:

3

Explanation:

5 0
4 years ago
Two samples of water are mixed together.
horrorfan [7]

Let the cold water go up x degrees.

Let the hot water go down 100 - x degrees.

The formula for heat exchange is m*c*delta t

Givens

Ice

deltat = x

m = 0.50 kg

c = 4.18

Hot water

deltat = 100 - x

m = 1.5 kg

c = 4.18

Formula

The heat up = heat down

0.50 * c * x = 1.5 * c * (100 - x)            Divide both sides by c

Solution

0.50 *x = 1.5*(100 - x)                          Remove the brackets.

0.5x = 150 - 1.5x                                  Add 1.5x to both sides.

0.5x + 1.5x = 150 - 1.5x + 1.5x             Combine like terms  

2x = 150                                               Divide by 2

x = 75

Answer

A

6 0
4 years ago
023 (part 1 of 2) 10.0 points
Annette [7]

Answer:

Part 1

The angular speed is approximately 1.31947 rad/s

Part 2

The change in kinetic energy due to the movement is approximately 675.65 J

Explanation:

The given parameters are;

The rotation rate of the merry-go-round, n = 0.21 rev/s

The mass of the man on the merry-go-round = 99 kg

The distance of the point the man stands from the axis of rotation = 2.8 m

Part 1

The angular speed, ω = 2·π·n = 2·π × 0.21 rev/s ≈ 1.31947 rad/s

The angular speed is constant through out the axis of rotation

Therefore, when the man walks to a point 0 m from the center, the angular speed ≈ 1.31947 rad/s

Part 2

Given that the kinetic energy of the merry-go-round is constant, the change in kinetic energy, for a change from a radius of of the man from 2.8 m to 0 m, is given as follows;

\Delta KE_{rotational} = \dfrac{1}{2}  \cdot I \cdot \omega ^2 = \dfrac{1}{2}  \cdot m \cdot v ^2

I  = m·r²

Where;

m = The mass of the man alone = 99 kg

r = The distance of the point the man stands from the axis, r = 2.8 m

v = The tangential velocity = ω/r

ω ≈ 1.31947 rad/s

Therefore, we have;

I = 99 × 2.8² = 776.16 kg·m²

\Delta KE_{rotational} = 1/2 × 776.16 kg·m² × (1.31947)² ≈ 675.65 J

3 0
3 years ago
A ball is dropped from rest from a tower and strikes the ground 125meters below. Approximately how many seconds does it take for
kogti [31]
Oh ok thanks i i miss me calf and she is going on the ground
4 0
3 years ago
Number 38 please!!!
vodomira [7]

Answer:

D. 30 Ω

Explanation:

R₁ + R₂ = 33

-0.0005 R₁ + 0.005 R₂ = 0

Solve the system of equations for R₁.

-0.0005 R₁ + 0.005 R₂ = 0

0.005 R₂ = 0.0005 R₁

R₂ = 0.1 R₁

R₁ + R₂ = 33

R₁ + 0.1 R₁ = 33

1.1 R₁ = 33

R₁ = 30

3 0
3 years ago
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