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3 years ago

Which of the following is true of the mass of an object?

Chemistry

1 answer:

shtirl [24]3 years ago

6 0

Answer:

Its mass is measured on a scale.

It is measured on a balance.

Explanation:

The mass of an object can easily be determined using a balance or weighing scale.

Mass is the amount of matter contained in a substance. it is has the same value every where and will not vary by geography or location.

Weight is the force on body due to gravity. It is a function of mass and acceleration due to gravity.

Both mass and weight are different.

They can both be measured using a weight device.

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joja [24]

This item is nondurable.

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3 years ago

What physical and chemical properties should braces (used to straighten teeth possess in order to attain its desired goal to str

Nitella [24]

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Explanation:

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2 years ago

Which form of energy is converted to thermal energy when propane burns in air?

kolezko [41]

Chemical because the propane has stored chemical energy which is being released and a by-product of that propane is heat or themal energy.

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2 years ago

2) Examine the molecules below.<br> Circle the molecules that can also be classified as compounds.

sergejj [24]

Answer:

3rd

Explanation:

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4 0

2 years ago

A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o

Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

$\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }$

where,

Diffusion rate of unknown gas = 155 mL/s

CO_2 diffusion rate = 102 mL/s

CO_2 molar mass = 44 g mol^-1

Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

$\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}$

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

4 0

3 years ago