What is one main difference between animal cells and plant cells?

To test the resiliency of its bumper during low-speed collisions, a 3 690-kg automobile is driven into a brick wall. The car's b

Mariana [72]

Answer:

1.8 m/s

Explanation:

m = mass of the automobile = 3690 kg

k = force constant of the spring = 8 x 10⁶ N/m

x = compression of the spring = 3.86 cm = 0.0386 m

v = speed of the car before impact

Using conservation of energy

Kinetic energy of automobile before impact = Spring potential energy of bumpers

(0.5) m v² = (0.5) k x²

(3690) v² = (8 x 10⁶) (0.0386)²

v = 1.8 m/s

8 0

3 years ago

The dimensions of information systems are people, organizations, and information technology.

Alchen [17]

Answer:

false

Explanation:

5 0

3 years ago

A 62 kg rock climber falls off the wall at the gym. Immediately before she hits the padded floor, her velocity is 7.9 m/s, 15° a

Kisachek [45]

Answer:

Explanation:

Given

mass of climber= 62 kg

velocity of climber before it hits=7.9 m/s at an angle of $15^{\circ}$ from vertical

therefore change in momentum in vertical direction is

$\Delta P=m(v_i-v_f)$

$\Delta P=62\left ( 7.9cos15-(7.9cos15)\right )$

$\Delta P=2\times \62\times 7.9cos15=946.22 N.s$

there is no change in horizontal momentum

and impulse=change in momentum

F.dt=946.22

$F=\frac{946.22}{0.75}=1.261 kN$

For non padded floor

$F=\frac{946.22}{0.25}=3748.88 =3.748 kN$

5 0

3 years ago

A river has a steady speed of 0.550 m/s. A student swims upstream a distance of 1.00 km and swims back to the starting point. If

nlexa [21]

Answer:

$t=564.83seconds=9.414minutes=0.1569hours$

Explanation:

Here the steady speed of the river water relative to ground is

$V_{wg}=0.55m/s$

Speed of the boy relative to still water is

$V_{BW}=1.50m/s$

Here we are considering +ve speed along along +ve x-axis and -ve speed along -ve x-axis

Therefore the speed of boy relative to the ground upstream is:

$V_{BGup}=V_{BW}-V_{WG}\\V_{BGup}=1.50m/s-0.550m/s\\V_{BGup}=0.95m/s$

And the speed of boy relative to the ground downstream is:

$V_{BGdown}=V_{BW}+V_{WG}\\V_{BGdown}=1.50m/s+0.550m/s\\V_{BGdown}=2.05m/s$

The distance covered in upstream trip d₁=1.0km=1000m and the distance covered in downstream is d₂=1.0km=1000m

Since time taken by a person is to cover distance d with speed v given by:

$t=d/v$

The total time taken for one trip is:

$t=\frac{d_{1} }{V_{BGup} } -\frac{d_{2} }{V_{BGdown} }\\t=\frac{1000m}{0.95m/s}-\frac{1000m}{2.05m/s}\\ t=564.83seconds=9.414minutes=0.1569hours\\$

3 0

3 years ago

What is the main way that scientists determine which conditions can support life

liraira [26]

Bacteria they use bacteria there’s a microscope thing in the area and I see a lot of things and if the bacteria is some type away then they would find a medicine to treat direct her than hope everybody else

3 0

3 years ago