Answer:
never ever ever never never ever :)
Explanation:
Answer:
b. There is no definite top to the atmosphere. The pressure and density gradually get smaller as the altitude gets larger.
Explanation:
There is no specific top of the atmosphere. It varies from place to place. But generally it is considered to be 480 kilometers thick. But majority of its thickness is limited to 16 km only above earth surface. The pressure and density gradually get smaller as the altitude gets larger. The air pressure at sea level is 14.7 pounds per square inch and it decreases to 10 pounds per square inch at a height of 3 kilometers. From the above discussion we say that option B is correct
Answer:
decreases, increases, minimum (zero)
Explanation:
Kinetic energy of a body is directly proportional to the square of velocity of the body and the potential energy is directly proportional to the height of the body at which it is placed.
The formula for the kinetic energy is
K = 1/2 m v^2
The formula for the potential energy is
U = m g h
As the body goes up its kinetic energy decreases as the velocity of the object decreases.
As the body goes up the potential energy increases as the height increases.
At the top most point, the velocity of teh object is zero, so the kinetic energy at the top is zero.
The answer is c. +2.0 µC
To calculate this, we will use Coulomb's Law:
F = k*Q1*Q2/r²
where F is force, k is constant, Q is a charge, r is a distance between charges.
k = 9.0 × 10⁹ N*m/C²
It is given:
F = 7.2 N
d = 0.1 m = 10⁻¹ m
Q1 = -4.0 µC = 4 * 1.0 × 10⁻⁶ = 4.0 × 10⁻⁶
Q2 = ?
Thus, let's replace this in the formula for the force:
7.2 = 9.0 × 10⁹ * 4.0 × 10⁻⁶ * Q2/(10⁻¹)²
7.2 = 9 * 4 * 10⁹⁻⁶ * Q2/10⁻¹°²
7.2 = 36 × 10³ * Q2 / 10⁻²
Multiply both sides of the equation by 10⁻²:
7.2 × 10⁻² = 36 × 10³ * Q2
⇒ Q2 = 7.2 × 10⁻² / 36 × 10³ = 7.2/36 × 10⁻²⁻³ = 0.2 × 10⁻⁵ = 2 × 10⁻⁶
Since µC = 1.0 × 10^-6:
Q2 = 2 * 1.0 × 10^-6 = 2 µC
